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3 years ago

Which of these statements is not true?

Chemistry

1 answer:

arlik [135]3 years ago

8 0

Answer:

Explanation:

should be different numbers of neutrons

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What is 0.0135 moles of in AlCl3 grams? Round to 3 sig figs

Mekhanik [1.2K]

Answer: 1.80g

Explanation:

Molar Mass of AlCl3 = 27 + (3x35.5)

= 27 + 106.5 = 133.5g/mol

Number of mole of AlCl3 = 0.0135mol

Mass = 0.0135 x 133.5= 1.80g

6 0

3 years ago

Calculate the enthalpy change for the reaction of hydrogen and chlorine using the bond energies below.

babunello [35]

Answer:

final-intial temperature= enthalpy change

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3 years ago

Ethan is investigating a snails response to stimuli. He put the following substances on each corner of a paper towel; syrup,lemo

olga nikolaevna [1]

There doesn't seem to be a clear answer, it is placed in the center when it's substances is on the corners it doesn't give anything else

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3 years ago

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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

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3 years ago

Which statement supports Newton’s first law of motion?

fenix001 [56]

C. Planets can move at a varying speed due to forces exerted in space.

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3 years ago

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