<em>I</em><em> </em><em>do</em><em> </em><em>not</em><em> </em><em>understand</em><em> </em><em>science</em><em> </em><em>but</em><em> </em><em>if</em><em> </em><em>u</em><em> </em><em>ask</em><em> </em><em>me</em><em> </em><em>I</em><em> </em><em>would</em><em> </em><em>have</em><em> </em><em>no</em><em> </em><em>clue</em><em> </em><em>do</em><em> </em><em>u</em><em> </em><em>get</em><em> </em><em>what</em><em> </em><em>I</em><em> </em><em>mean</em>
I believe it’s Chemical energy but please correct me if i’m wrong
Here is an acid-base reaction. Hydrochloric acid (HCl) reacts with strontium hydroxide [ Sr(OH)2 ]
Ions H+ and OH- neutralize each other. If the amounts are not equal, one of them will be in excess.
Follow the steps as
1. Find moles of ions: mole= Molarity * Volume (in liter) ; n= M * V OR millimole = Molarity * Volume (in ml) ;
2. Write the equation
3. Find out excess ion
4. Use final volume (V acid + V base ) to calculate concentration of excess ion.
n HCI = 28 ml * 0.10 M = 0.28 mmol, releases 0.28 mmol H+ ions
n Sr(OH)2= 60 ml * 0.10 M= 0.60 mmol, releases 2* 0.60=1.20 mmol OH- ions
since Sr(OH)2⇒ Sr2+ + 2OH-
Neutralization reaction is OH- + H+ ---> H2O. The ratio is 1:1. That means 1 mmol hydroxide ions will neutralize 1 mmol hydrogen ions. Since OH- ions are greater in amount, they will be in excess
n(OH-) - n(H+)= 1.20 - 0.28 = 0.92 mmol OH- ions UNREACTED.
Total volume= V acid + V base= 28 ml + 60 ml = 98 ml
Molarity of OH- ions= mole / Vtotal = 0.92/98= 0.009 M
The answer is 0.009 M.
Answer:
There are way in separating mixtures of chloride salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration, and sublimation. The easiest method among the three is separation by sublimation.
Protons and neutrons are found inside the nucleus
