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geniusboy [140]
3 years ago
11

is the change in potential energy the same when you slide an object up an incline or when you lift it upwards?​

Physics
1 answer:
chubhunter [2.5K]3 years ago
3 0
When you lift it upwards
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Scientific way of thinking
noname [10]

Answer:

huh,? can you explain the question more please

7 0
4 years ago
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A student placed a ladder up against a wall as shown below. The normal force applied by the wall in the ladder will be directed:
solmaris [256]
The normal force is always perpendicular to the surface. So it would be straight to the left of the wall
6 0
4 years ago
In one contest at the county fair, a spring-loaded plunger launches a ball at a speed of 3.2m/s from one corner of a smooth, fla
lara31 [8.8K]

Answer:

Explanation:

Given

Speed of ball u=3.2\ m/s

Plane is inclined at an angle 20^{\circ}

To win the Game we need to hit the target at x=2.4\ m away

Launch angle of ball \theta

Motion of ball can be considered in two planes i.e. Vertical to the plane and horizontal to the plane

So Net acceleration in vertical plane is g\sin 20

Range of Projectile is given by

R=\frac{u^2\sin 2\theta }{g}

for R=2.4\ m

2.4=\frac{3.2^2\times sin 2\theta }{g\sin 20}

\sin 2\theta =\frac{2.4\times 9.8\times \sin 20}{3.2^2}

\sin 2\theta =0.7855

2\theta =51.77

\theta =25.88^{\circ}

so ball must be launched at an angle of 25.88^{\circ}

4 0
3 years ago
the end of the tracks, 8.8 m lower vertically, is a horizontally situated spring with constant 5 × 105 N/m. The acceleration of
devlian [24]

Answer

Assuming the mass of the car, m = 43000 kg

initial speed u = 0

vertical distance moved, h = 8.8 m

spring constant k = 5 x  10⁵ N / m

acceleration of gravity = 9.8 m/s²

From law of conservation of energy ,

Gravitational potential energy at starting position =potential energy of the spring at maximum compression

                m g h =\dfrac{1}{2}k x^2

                x = \sqrt{\dfrac{2mgh}{k}}

                x = \sqrt{\dfrac{2\times 43000\times 9.8\times 8.8}{5\times 10^5}}

                    x = 14.83 m

If the mass of the car is equal to 43000 Kg the spring is compressed to 14.83 m

6 0
4 years ago
A truck of mass 500kg moving at 4m/s collides with another truck of mass 1500kg moving in the same direction at 2m/s. What is th
VMariaS [17]

Answer:

m1u1+m2u2=(m1+m2)v.

500×4+1500×2=(500+1500)V.

2000+3000=2000V.

5000=2000V.

V=2.5m/s

8 0
3 years ago
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