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alekssr [168]
3 years ago
10

What are the differently types of motion in a bicycle?

Physics
1 answer:
Ksivusya [100]3 years ago
7 0
The two types of motion exerted in bicycle are:
1. rotary motion
2. linear motion
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A bucket filled woth water seems light while it sinks into water.Also show their relation using formula
slavikrds [6]

Answer: This phenomenon happens due to upthrust exerted by water.

Explanation:

We know that,

Liquid Pressure is directly proportional to the height of the vertical column in the liquid.(P∝h)

When a bucket filled water is sunk into the water container, there occur difference in the pressure in top and bottom of the water container. Due to this, water exerts an upward force on the bucket filled with water. This is called Uprthrust.

Upthrust on the bucket makes the bucket filled with water lose some of it's weight and causes apparent loss in weight.

Hence, the bucket filled with water seems light while it sinks into water.

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3 years ago
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Mademuasel [1]

Answer:

An electric chemical cell is not always needed to have a power circuit. But every other part is.

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3 years ago
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Can someone please help me with science.
alekssr [168]

Answer:

The answers to your questions are given below

Explanation:

22. The energy of an electromagnetic wave and it's frequency are related by the following equation:

E = hf

Where:

E => is the energy

h => is the Planck's constant

f => is the frequency

From the equation i.e E = hf, we can conclude that the energy of a wave is directly proportional to it's frequency. This implies that an increase in the frequency of the wave will lead to an increase in the energy of the wave and also, a decrease in the frequency will lead to a decrease in the energy of the wave.

23. Gamma ray and radio wave are both electromagnetic waves. All electromagnetic waves has a constant speed of 3×10⁸ m/s in space.

Thus, gamma ray and radio wave have the same speed in space.

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3 years ago
The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very
BabaBlast [244]

Answer:

The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.

Explanation:

A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.

Let us find the drag force which is proportional to the velocity of two conducting plates.

The EMF that is induced in the eddy currents are : $E=v(B \times L)$

The force which is due to the induced magnetic field is, $F=l(L \times B)$

Therefore, $F=\frac{E}{R} \times (L \times B)$

                 $F=\frac{v(B \times L)}{R} \times (L \times B)$

Here, force is directly proportional to the velocity of the two conducting plates.

Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.  

6 0
3 years ago
A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above
nydimaria [60]

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

Explanation:

From the question we are told that

   The mass of the rock is  m = 0.250 \ kg

    The length of the string is  L = 0.75 \  m

    The angle the string makes horizontal is  \theta  = 11.9^o

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  \phi = 34.6^o

    The angular velocity of the rock is  w = 2.50 rev/s  = 2.50 * 2\pi  =15.7 \ rad/s

Generally the radius of the circle made by the length of the string is mathematically represented as

               r = L cos(\theta )

=>            r = 0.75  cos(11.9 )

=>            r = 0.734 \ m

Generally the resultant tangential velocity is mathematically represented as

      v__{R}}  = w * r

=>  v__{R}}  = 15.7  *0.734

=>  v__{R}}  =  11.5 \ m/s

Generally the tangential velocity along the x-axis is  

      v_x  = -v__{R}} *  sin(\phi)

=>   v_x  =- 11.5 *  sin(34.6)

=>   v_x  = -6.543 \ m/s

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      v_y = v__{R}} *  cos(\phi)

=>   v_y  = 11.5 *  cos(34.6)

=>   v_y  = 9.47 \ m/s

Generally the tangential velocity along the y-axis is  

      v_z = v__{R}} *  cos(90)

=>   v_z = 0 \ m/s

Generally the tangential velocity at that instant is mathematically represented as

       v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

8 0
3 years ago
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