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3 years ago

What are the differently types of motion in a bicycle?

Physics

1 answer:

Ksivusya [100]3 years ago

7 0

The two types of motion exerted in bicycle are:
1. rotary motion
2. linear motion

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Why do people act rude towards their supervisors

faltersainse [42]

Because people do not like being told what to do.

8 0

3 years ago

Suppose a grower sprays (8.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water

____ [38]

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

m is mass of water
c is specific heat capacity of water
ΔФ is change in temperature = Фf - Фi

when water freezes, the temperature, Фf = 0 °C

Q = 82 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

Learn more about heat flow here: brainly.com/question/14437874

6 0

2 years ago

An electron is released 7.2 cm from a very long nonconducting rod with a uniform 6.3 μc/m. what is the magnitude of the electron

nignag [31]

Acceleration = charge*Electric field / mass

6 0

3 years ago

BB8 is an intergalactic robot (essentially a soccer ball with a half meter radius that can control how fast it rolls around) tha

hram777 [196]

Answer:

20 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

r = Radius of robot = 0.5 m

$\alpha$ = Angular acceleration = 2 rad/s²

Linear acceleration is given by

$a=r\alpha\\\Rightarrow a=0.5\times 2\\\Rightarrow a=1\ m/s^2$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 50=0t+\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow t=10\ s$

While speeding up time taken is 10 seconds

$v=u+at\\\Rightarrow v=0+1\times 10\\\Rightarrow v=10\ m/s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 50=10t-\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow 50=10t-0.5t^2\\\Rightarrow -5t^2+100t-500=0$

$t=\dfrac{-100\pm \sqrt{100^2-4\left(-5\right)\left(-500\right)}}{2\left(-5\right)}\\\Rightarrow t=10\ s$

The time taken to slow down is 10 seconds

Total time the trial is rum is 10+10 = 20 seconds

6 0

3 years ago

Energy conversion from potential energy (the energy of position or composition) to kinetic energy (the energy of motion) is illu

zhannawk [14.2K]

<h2>The following is an elaboration of the differences in potential and kinetic energies based on the diagram of the roller coaster: </h2>

When the coaster is in position A, the potential energy is maximum and the kinetic energy is minimum.
As the coaster moves to position B, the potential energy is minimum and the kinetic energy is maximum .
As momentum carries the coaster into position C, the potential energy is minimum and the kinetic energy is maximum.
Finally, as the coaster reaches position D, the potential energy is maximum and the kinetic energy is minimum.

5 0

2 years ago