Answer:
Accelerate up more compressed spring
Accelerate down spring less compressed
Explanation:
For this problem we must analyze the forces that act on the scale on the one hand the weight of the man directed downwards and I have the other the elastic force of the spring directed upwards. Now let's write Newton's second law for these forces in various configurations,
When the elevator is quiet or moving at constant speed
Fe - W = 0 ⇒ Fe = W -k x = mg x = mg /k
Fe = mg
We use this value to compare
Now let's analyze when the elevator accelerates upwards
Fe -W = m a
Fe = ma + W
Fe = m (a + g)
So we can see that Fe increases, so the compression of springs is higher
Now let's analyze when the elevator acceleration is down
Fe -W = m (-a)
Fe = w - m a
Fe = m (g -a)
In this case Fe is smaller, so the compression of the spring is less
The position of the particle when it changes direction is x = 3.0 m
Explanation:
The position of the particle is given by the equation
In order to determine its position when it changes direction, we need to find the time t at which the velocity of the particle becomes zero.
The velocity of the particle si given by the derivative of the position, therefore:
The velocity is zero when:
And therefore, the position at t = 0.41 s is
Learn more about position and velocity:
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The amplitude of a sound wave is a reflection of how much energy is carried, which contributes to the intensity of the sound. Intensity is measured in decibels and is perceived as sound volume. Thus, the volume is proportional to the amplitude of the sound wave. The frequency of a sound wave is perceived as pitch.
