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GalinKa [24]
2 years ago
6

The reaction of 60.0 g of aluminum oxide with 30.0 g of carbon produced CO gas and 22.5 g of aluminum metal. What is the percent

yield aluminum for this reaction?
Chemistry
1 answer:
natulia [17]2 years ago
5 0

Answer:

The answer to your question is: 70.8%

Explanation:

Data

Al₂O₃ = 60 g

C = 30 g

CO = gas

Al = 22.5 g

MW Al₂O₃ = 102 g

MW C = 12 g

MW Al = 54 g

Reaction

                 Al₂O₃    +     3C     ⇒       3 CO    +    2 Al

Limiting reactant

                            102 g of Al₂O₃  -------------- 54 g Al

                             60 g                 --------------   x

                             x = 31.8 g

                            36 g of C ------------------ 54 g of Al

                            30 g of C ------------------  x

                            x = 45 g of Al

Limiting reactant = Al₂O₃

Percent yield = \frac{22.5}{31.8} x 100

Percent yield = 70.75 %

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Explanation:

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b)

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