Question

The reaction of 60.0 g of aluminum oxide with 30.0 g of carbon produced CO gas and 22.5 g of aluminum metal. What is the percent yield aluminum for this reaction?

Answer 1

Answer:

The answer to your question is: 70.8%

Explanation:

Data

Al₂O₃ = 60 g

C = 30 g

CO = gas

Al = 22.5 g

MW Al₂O₃ = 102 g

MW C = 12 g

MW Al = 54 g

Reaction

                 Al₂O₃    +     3C     ⇒       3 CO    +    2 Al

Limiting reactant

                            102 g of Al₂O₃  -------------- 54 g Al

                             60 g                 --------------   x

                             x = 31.8 g

                            36 g of C ------------------ 54 g of Al

                            30 g of C ------------------  x

                            x = 45 g of Al

Limiting reactant = Al₂O₃

Percent yield = $\frac{22.5}{31.8} x 100$

Percent yield = 70.75 %