Correct answer is option E. <span>It is a redox reaction in which Zn is oxidized at the anode, and V is reduced at the cathode.
Reason:
In above reaction, the oxidation state of VO3- is +5, while that of VO2 is +4. Thus there is reduction of V from +5 to +4
In case of Zn, oxidation state of Zn is increased from 0 to +2, Thus process is referred as oxidation. </span>
Answer:
H₂: 0.48, N₂: 0.43; Ar: 0.09
Explanation:
First of all, sum all the pressures to know the total pressure in the mixture.
434 Torr + 389.9 Torr + 77.9 Torr = 901.8 Torr
Mole fraction = Pressure gas / Total Pressure
Mole Fraction H₂: 434 Torr /901.8 Torr = 0.48
Mole Fraction N₂: 389.9 /901.8 Torr =0.43
Mole Fraction Ar: 77.9 /901.8 Torr = 0.09
Remember: <u>SUM OF MOLE FRACTION = 1</u>
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is
a hydroxy ketone attached to two phenyl groups.</span><span>
To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the
oxidation of benzoin by ammonium nitrate is:
</span>2Ph-C(OH)-C(O)-Ph+NH4NO3
--> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>
<span>
</span><span>I hope this helps and if you have any
further questions, please don’t hesitate to ask again.</span>
<span>
<span>
</span></span>Volume = 4/3 * PI * r^3
1.59 x 10^24 copper atoms = 2.64 moles of copper
Atomic Mass of copper = 63.55
2.64 * 63.55 = 167.77 grams of copper
Volume of Copper = Mass / Density
Volume of Copper = 167.77 grams / 8.96
Volume of Copper = <span>
<span>
18.72</span></span> cubic centimeters
r^3 = Volume / (4/3 * PI)
r^3 = 18.72 / 4.188
r^3 =
<span>
<span>
<span>
4.47
radius = </span></span></span><span><span><span>1.647</span> centimeters
</span></span>
Answer:
a) kc= [SO3 ]/([SO2 ][O2 ])
b) kc= 2.27*10⁶ M⁻¹
v) the reaction is product-favored
Explanation:
for the reaction, the equilibrium constant is
SO2 (g) + O2 (g) <-----> SO3 (g)
he equilibrum constant is
kc= [SO3 ]/([SO2 ]*[O2 ])
replacing values
kc= [SO3 ]/([SO2 ]*[O2 ]) = 1.01*10⁻² M/(3.61*10⁻³M*6.11 x 10⁻⁴ M) = 2.27*10⁶ M⁻¹
since kc>>1 the reaction is product-favored