Answer:
224.28 g of W, are in 1.22 moles of it
Explanation:
This can be made by a rule of three:
1 mol of Tungsten (W) weighs 183.84 grams
1.22 mol of W, would weigh 224.28 g (1.22 . 183.84)
Molecular weight (mass):
It is the molecular mass of a substance that can be calculated by sum of atomic weight of atoms that are present in the molecule multiple by the total number of molecule.
In KOH,
Atomic weight of K=39.1
Atomic weight of O=15.9
Atomic weight of H=1
Molecular weight=Atomic weight of K+Atomic weight of O+Atomic weight of H
=56.1 g/mol
So the answer is A that is 56.10 g/mol
Answer:
The answer to your question is it is not at equilibrium, it will move to the products.
Explanation:
Data
Keq = 2400
Volume = 1 L
moles of NO = 0.024
moles of N₂ = 2
moles of O₂ = 2.6
Process
1.- Determine the concentration of reactants and products
[NO] = 0.024 / 1 = 0.024
[N₂] = 2/1 = 2
[O₂] = 2.6/ 1= 2.6
2.- Balanced chemical reaction
N₂ + O₂ ⇒ 2NO
3.- Write the equation for the equilibrium of this reaction
Keq = [NO]²/[N₂][O₂]
- Substitution
Keq = [0.024]² / [2][2.6]
-Simplification
Keq = 0.000576 / 5.2
-Result
Keq = 1.11 x 10⁻⁴
Conclusion
It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-
1.11 x 10⁻⁴ < 2400
D that is the correct answer