

- <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

The coordinates of G = ( -6 , 5 )
The coordinates of H = ( 2 , - 7 )
<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

- <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>
<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>








(x+2)(x+8) = x^2 +10x +16
(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1
Answer:
a. 5:2
Step-by-step explanation:
1 ft = 12 in
30:12
Divide by 6
30÷6=5
12÷6=2
So, the answer is 5:2
The answer is C. 8. Then both can have a denominator that looks like this..
6/8 and 5/8. Hope it helps!
Answer:
Using the formula:

where
A is the total amount
P is the principal
I is the Simple Interest
As per the statement:
Principal(P) = 5300 rupees.
rate of interest(r) = 6.5% = 0.065
Total amount(A) = 6678 rupees.
Then using above formula we have;

Subtract 5300 both sides we get;

or

We have to find the time period.
Using formula of Simple interest:

where r is the rate of interest (in decimal)
here, r = 6.5% = 0.065
Substitute the given values top find t:

⇒
Divide both sides by 344.5 we have;

Therefore, the time period t in years is 4 years