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AnnyKZ [126]
3 years ago
11

Brian was asked to write x72 as a product of 2 powers with the same base in 4 different ways, using only positive exponents.

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0

The equivalent expression to the value given using the laws of indices is  {x}^{4(18)}

Evaluating the options given based on the laws of indices :

  • {x}^{8}. {x}^{9}  =  {x}^{8 + 9}  =  {x}^{17}
  • {x}^{35}. {x}^{47}  =  {x}^{35 + 47}  =  {x}^{82}
  • {x}^{4(18)}  =  {x}^{4 \times 18}  =  {x}^{72}
  • {x}^{24}. {x}^{3}  =  {x}^{24 + 3}  =  {x}^{27}

Therefore, the only expression which would give a correct way of representing {x}^{72} \: is \: {x}^{4(18)}

Learn more : brainly.com/question/12937923?referrer=searchResults

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The expression below is scientific notation for what number?<br> 6.1 x 10^6
arlik [135]

Scientific notation is a way to write compactly numbers with lots of digits, either because they're very large (like 2393490000000000000000000), or very small (like 0.0000000000356).

We use powers of ten to describe all those leading/trailing zeros, so that we con concentrate on the significat digits alone.

In your case, the "important" part of the number is composed by the digits 6 and 1, all the other digits are zero. But how many zeroes? Well, let's do the computation.

Every power of 10, 10^n is written as one zero followed by n zeroes, so we have

10^6 = 1000000 \implies 6.1 \times 10^6 =6.1 \times 1000000

Multiplying a number by 10^n means to shift the decimal point to the right and/or add trailing zeroes n times. So, we have to repeat this process six times. We shift the decimal point to the right one position, and then add the five remaning zeroes. The result is thus

6.1 \times 1000000 = 6100000

4 0
3 years ago
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3 years ago
A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs
Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

C = \frac{N!}{(N-K)!*K!}

For the juniors we have N = 13 and K = 6

Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

For the seniors we have N = 16 and K = 8

Cs = \frac{16!}{8!8!}  = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0
3 years ago
Find the slope of the graph of x^3 = ln(xy) at the point (1, e).
kkurt [141]

Answer:

e^x^3 = xy : e^x^3 = xy

Step-by-step explanation:

=)

6 0
2 years ago
B.<br>Find the compound interest on N 8000, 00 for 3 years at 5% per annum​
balu736 [363]

Answer:

926,100

Step-by-step explanation:

you will have earned in 126,100 in interest

5 0
3 years ago
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