8 + 15 = 23
23 - 65.45 = 42.46.
The rest of the people in the group split $42 and 46 cents.
Hope this helped!!
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
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Answer:
First "order of operations" mistake: step 2
First arithmetic mistake: step 4
Step-by-step explanation:
As we understand Rena's work, she wants to simplify ...
for x = -1 and y = 2.
Her work seems to be ...
<u>Step 1</u>
<u>Step 2</u>
<u>Step 3</u>
<u>Step 4</u>
_____
So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...
__
We expect your answer is supposed to be Step 4.
