We have a line y = 1/3x -6
We want a line that is perpendicular to this line
Perpendicular lines have slopes that multiply to -1
1/3 * m = -1
3 * 1/3 *m = -1 * 3
m = -3
The slope of the perpendicular line is -3
y = mx+b where m is the slope and b is the y intercept
y = -3x+b
We have a point on the line ( 7 ,-23)
Substitute this point into the equation
-23 = -3(7)+b
-23 = -21+b
Add 21 to each side
-23+21 = -21+21+b
-2 = b
y = -3x-2
In slope intercept form, the line perpendicular passing through (7,-23) is
y = -3x-2
Answer:
7cm
Step-by-step explanation:
One side of a square is increased by 8 cm, let us say the length got increased by 8 cm. So we have length of x + 8 cm
An adjacent side, the width, decreased by 2 cm. So we have width of x - 2cm
Perimeter of rectangle = 2(length + width)
40 = 2( (x + 8) + ( x - 2) )
40 = 2( 2x + 6)
40 = 4x + 12
28 = 4x
x = 7 cm
That is 7 cm of the length of the side of the square
Points
on the circle satisfy
.
Points inside the circle satisfy
.
Points outside the circle satisfy
.
We have

so the point (2, 8) lies inside the circle.