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Murljashka [212]
3 years ago
12

if the velocity of a moving car increases from 9.0 m/s to 25.0 m/s in the span of 5.0 seconds, what is the average acceleration

during this time period, in m/s2
Chemistry
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

3.5m/s²

Explanation:

Logic...

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GIVING BRAINLIEST, FIVE STARS AND THANKS!!!!
Alisiya [41]

Answer:

Fission is the splitting of a large atom into two or more smaller ones. Fusion is the fusing of two or more lighter atoms into a larger one. Fission reaction does not normally occur in nature.

Explanation:

Quizlet

6 0
3 years ago
Read 2 more answers
Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
There are 1.2 x 1024 formula units
____ [38]

mol CaCl₂ = 1.2 x 10²⁴ : 6.02 x 10²³ = 1.993

mass = 1.993 x 111 g/mol = 221.223 g

4 0
2 years ago
Round off or add zero to the following calculated answers to give a final answer with three significant figures: 3.528x10exponen
Readme [11.4K]
352.8
with this all you have to do is move the decimal point to the right 2 times.
5 0
4 years ago
Balance the redox reaction below in acidic solution. pbo2(s) + i-(aq) pb2+(aq) + i2(s) when balanced what is the sum of all the
chubhunter [2.5K]
Two Half Cell reactions are as,

Reduction:                   PbO₂  +  2e⁻   →     Pb²⁺  

As it is acidic medium reaction, so add H⁺ on reactant side as it has more number of oxygen atoms and add H₂O on product side, and balance tehe elements, So,
                             4 H⁺     +   PbO₂  +  2e⁻   →     Pb²⁺   +    2 H₂O      (1)

Oxidation:                        I⁻     →     I₂   +  1e⁻

Balance Number of elements along with electrons,

                                        2 I⁻     →     I₂   +  2e⁻                                    (2)

Compare eq. 1 and 2,

                             4 H⁺     +   PbO₂  +  2e⁻   →     Pb²⁺   +    2 H₂O

                                                           2 I⁻     →     I₂   +  2e⁻ 
                            ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
                            PbO₂  +  2 I⁻  +  4 H⁺     →     Pb²⁺  +  I₂  +  2H₂O


                                   Number of Coefficients  =  11
6 0
4 years ago
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