Answer:
Molarity Problems Worksheet
M=nV n= # moles
V must be in liters (change if necessary)
1. What is the molarity of a 0.30 liter solution containing 0.50 moles of NaCl?
1.7M
2. Calculate the molarity of 0.289 moles of FeCl3 dissolved in 120 ml of solution?
2.41 M
3. If a 0.075 liter solution contains 0.0877 moles of CuCO4, what is the molarity?
1.2M
4. How many moles of NaCl are present in 600. ml a 1.55 M NaCl solution?
.930 moles
5. How many moles of H2SO4 are present in 1.63 liters of a 0.954 M solution?
1.56 molse
6. How many liters of solution are needed to make a 1.66 M solution containing 2.11 moles of KMnO4?
1.27 g
7. What volume of a 0.25 M solution can be made using 0.55 moles of Ca(OH)2?
2.2 L
For all of the problems below you will need to do a mole-mass conversion. Each problem will involve two steps.
8. What is the molarity in 650. ml of solution containing 63 grams of NaCl?
1.7 M
9. How many grams of Ca(OH)2 are needed to produce 500. ml of 1.66 M Ca(OH)2 solution?
61.5 g
10. What volume of a 0.88 M solution can be made using 130. grams of FeCl2?
1.2 L
Dilution Problems Worksheet
1. How do you prepare a 250.-ml of a 2.35 M HF dilution from a 15.0 M stock solution?
39.2 mL
2. If 455-ml of 6.0 M HNO3 is used to make a 2.5 L dilution, what is the molarity of the dilution?
1.1 M
3. If 65.5 ml of HCl stock solution is used to make 450.-ml of a 0.675 M HCl dilution, what is the molarity of the stock solution?
4.64 M
4. How do you prepare 500.-ml of a 1.77 M H2SO4 dilution from an 18.0 M H2SO4 stock solution?
Take 49.2-ml of 18.0 M H2SO4 stock solution and pour it into a 500-ml volumetric flask. Fill to the 500-ml line with distilled water to make 1.77M H2SO4 solution.
Extra Molarity Problems for Practice
1. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5 L?
3.75 M
2. How many moles of Sr(NO3)2 would be used in the preparation of 2.50 L of a 3.5 M solution?
8.75 M
3. What is the molarity of a 500-ml solution containing 249 g of KI?
3.00 M
4. How many grams of CaCl2 would be required to produce a 3.5 M solution with a volume of 2.0 L?
777 g
Explanation:
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