Answer:
When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L
Explanation:
Step 1: Data given
Volume of the gas = 32.00 L
Pressure of the gas = 1.59 atm
Temperature and moles of gas stay constant
the pressure of the vessel is decreased by a factor of three
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the initial pressure = 1.59 atm
⇒with V1 = the initial volume = 32.00 L
⇒with P2 = the decreased pressure = 1.59 / 3 = 0.53 atm
⇒with V2 = the new volume = TO BE DETERMINED
1.59 atm * 32.00 L = 0.53 atm * V2
V2 = (1.59 * 32.00 L) / 0.53 atm
V2 = 96.00 L
When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L
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Answer:
To determine the amount of heat the gold has absorbed to melt, we simply multiply the mass of the block of ice to the heat of fusion of water which is given above. We calculate as follows:
Heat = 20.0 g (35.4 g)
Heat = 1290 J
<h3>
Answer:</h3>
0.819 mol Ag
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
4.93 × 10²³ atoms Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.818665 mol Ag ≈ 0.819 mol Ag