Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Answer:
Step-by-step explanation:
Tye length of the ramp can be gotten using Pythagoras theorem.
Horizontal distance = 10ft.
Vertical distance = 3ft
Length of the ramp² = 10²+3²
Length of the ramp² = 100+9
Length of the ramp² = 109
L² = 109
L =√109
L = 10.44ft
Hence the length of the ramp is 10.4ft to the nearest tenth
Answer:
93
Step-by-step explanation:
Add: 67+41+91+68=267
Subtract: 360-267=93
Hope this helps