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Vitek1552 [10]
3 years ago
10

The endpoints of a diameter of a circle are ​A(3​,​1) and ​B(8​,13​). Find the area of the circle in terms of pi.

Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer:

A = 169π/4

Step-by-step explanation:

From these two given points we find the length of the diameter of this circle, using the Pythagorean Theorem:

d^2 = (8 - 3)^2 + (13 - 1)^2, or

d^2 = 25 + 144 = 169

Thus, the diameter, d, of this circle is √169, or 13.  

The radius is thus 13/2 units.

The area formula is A = πr^2.  Here the area is

A = π(169/4), or A = 169π/4

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Step-by-step explanation:

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Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

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3 years ago
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