6x3=18 add two zeros and you get 1800 seconds:) hope this helped
You subtract 3 miles from the 5.5 miles which gives you 2.5
4 x -5 = -20 then 12 + -20 = -8
Answer:
Step-by-step explanation:
0 = x2 + 3x - 10
10 = 2x+3x
10 = 5x
x = 2
0x = 5.2
0x = 10
x = 10.2 = 20
x = 20
0x = -5.-2
0x = -10
x = -10.2 = -20
x = -20
x = -5.2
x = -10
x = 5-2
x = 3
GOOD LUCK ! ;)
Answer: 0.93 radians & 2.21 radians
<u>Step-by-step explanation:</u>
![-4sin^2\theta-3sin\theta+5=0\\\\\text{Since this is not factorable, use the quadratic formula to find the roots:}\\\\sin\theta=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(-4)(5)}}{2(-4)}\\\\\\.\quad=\dfrac{3\pm \sqrt{9+80}}{-8}\\\\\\.\quad=\dfrac{3\pm\sqrt{89}}{-8}\\\\\\.\quad=\dfrac{3\pm9.43}{-8}\\\\\\.\quad=\dfrac{12.43}{-8}\quad and\quad \dfrac{-6.43}{-8}\\\\\\.\quad=-1.55\quad and\quad 0.80\\\\\\\theta=sin^{-1}(-1.55)\quad and\quad \theta=sin^{-1}(0.80)](https://tex.z-dn.net/?f=-4sin%5E2%5Ctheta-3sin%5Ctheta%2B5%3D0%5C%5C%5C%5C%5Ctext%7BSince%20this%20is%20not%20factorable%2C%20use%20the%20quadratic%20formula%20to%20find%20the%20roots%3A%7D%5C%5C%5C%5Csin%5Ctheta%3D%5Cdfrac%7B-%28-3%29%5Cpm%20%5Csqrt%7B%28-3%29%5E2-4%28-4%29%285%29%7D%7D%7B2%28-4%29%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B3%5Cpm%20%5Csqrt%7B9%2B80%7D%7D%7B-8%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B3%5Cpm%5Csqrt%7B89%7D%7D%7B-8%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B3%5Cpm9.43%7D%7B-8%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B12.43%7D%7B-8%7D%5Cquad%20and%5Cquad%20%5Cdfrac%7B-6.43%7D%7B-8%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D-1.55%5Cquad%20and%5Cquad%200.80%5C%5C%5C%5C%5C%5C%5Ctheta%3Dsin%5E%7B-1%7D%28-1.55%29%5Cquad%20and%5Cquad%20%5Ctheta%3Dsin%5E%7B-1%7D%280.80%29)
![\theta=not\ valid\qquad and\quad \theta=0.927](https://tex.z-dn.net/?f=%5Ctheta%3Dnot%5C%20valid%5Cqquad%20and%5Cquad%20%5Ctheta%3D0.927)
![\theta = 0.927\ radians\text{\ in the 1st quadrant and}\\\pi-0.927=2.21\ radians\text{\ in the 2nd quadrant}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%200.927%5C%20radians%5Ctext%7B%5C%20in%20the%201st%20quadrant%20and%7D%5C%5C%5Cpi-0.927%3D2.21%5C%20radians%5Ctext%7B%5C%20in%20the%202nd%20quadrant%7D)