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Mg + HCl → MgCl₂ + H₂
Balance Cl.
1 on the left, 2 on the right. Add a coefficient of 2 in front of HCl.
Mg + 2HCl → MgCl₂ + H₂
Balance H.
2 on the left, 2 on the right. Already balanced.
Balance Mg.
1 on the left, 1 on the right. Already balanced.
Our final balanced equation: Mg + 2HCl → MgCl₂ + H₂
Hope this helps!
Answer:
Explanation:
cold and hot are temperatures
Answer:
092) Icosane
093) Ethene
Explanation:
092) The given compounds are;
Decane C₁₀H₂₂; Viscosity = 0.850 mPa·s (25°C)
Ethene C₂H₄ (gas); Viscocity ≈ 0.01038 m
Icosane C₂₀H₄₂; Solid at room temperature
Methane CH₄; gas at room temperature
The viscosity of the given carbon and hydrogen compounds is observed to increase with their molar masses
Therefore, icosane, which is a solid at room temperature, has the highest viscosity (resistance to deformation) out of the given compounds
093) Polymers are made from monomer alkene units, therefore, ethene, which is the only alkene among the given compounds can be used to produce a polymer
Polyethene is formed by the polymerization of ethene whereby molecules of ethene are joined together to form poly(ethene)
Answer: The pressure in torr is 461 torr
Explanation:
To calculate the relation of density and molar mass of a compound, we use the ideal gas equation:
PV=nRT
P = pressure
V = Volume
n = number of moles
R = gas constant = 0.0821 Latm/Kmol
T = temperature =
Number of moles (n) can be written as:
where, m = given mass
M = molar mass = 44 g/mol
where,
where d = density = 2.54 g/L
The relation becomes:
PM=dRT
(760torr=1atm)
Thus the pressure in torr is 461 torr
Answer:
The major product is 2-methyl-2-pentene [ CH₃-CH₂-CH=C(CH₃)₂ ] and a minor product 2-methyl-1-pentene [ CH₃-CH₂-CH₂-C(CH₃)=CH₂ ].
Explanation:
Dehydration reaction is a reaction in which a molecule loses a water molecule in the presence of a dehydrating agent like sulfuric acid (H₂SO₄).
<u>Dehydration reaction of 2-methyl-2-pentanol</u> gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.
CH₃-CH₂-CH₂-C(CH₃)₂-OH (2-methyl-2-pentanol)→ CH₃-CH₂-CH=C(CH₃)₂ (2-methyl-2-pentene, major) + CH₃-CH₂-CH₂-C(CH₃)=CH₂ (2-methyl-1-pentene, minor)
<u>Since more substituted alkene is more stable than the less substituted alkene. So, the trisubstituted alkene, 2-methyl-2-pentene is more stable than the disubstituted alkene, 2-methyl-1-pentene.</u>
<u>Therefore, the trisubstituted alkene, 2-methyl-2-pentene is the major product and the disubstituted alkene, 2-methyl-1-pentene is the minor product.</u>
