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3 years ago

11

Which best describes most covalent compounds? A.soft B.brittle C.cold D.warm

2 answers:

Vera_Pavlovna [14]3 years ago

8 0

Answer:

Option one

Explanation:

Because I just took the test

SIZIF [17.4K]3 years ago

6 0

Answer:soft

Explanation:

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In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

Likurg_2 [28]

The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
(HBr) (KOH)

Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M

Concentration of KOH is 0.9756 M.

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3 years ago

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Which of the following elements will form a positive ions? check all that apply

tamaranim1 [39]

we're the rest of the question

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3 years ago

Which piece of glassware shown below is used to hold and dispense a solution of known concentration during a titration?

Musya8 [376]

Answer:

Answer C

Explanation:

Got it off of q**zlet ;)

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2 years ago

Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/

ankoles [38]

The balanced chemical equation for the combustion of butane is:

$2C_{4}H_{10}(g) +13 O_{2}(g)-->8CO_{2}(g)+10H_{2}O(g)$

Δ $H_{reaction}^{0}$ = Σ $n_{products}$ Δ $H_{f}^{0}_{(products)}$ -Σ $n_{reactants}$ Δ $H_{f}^{0}_{(reactants)}$

= $[{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]$ =[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

= -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

$1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}$

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0

3 years ago

What is the angle between the carbon-oxygen bond and one of the carbon-fluorine bonds in the carbonyl fluoride ( cof2 ) molecule

kozerog [31]

It has a trigonal planar structure. So, the calculated angle is 127.3 degrees.
You can see the structure in the picture.

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3 years ago

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