Answer:
Boron Carbonate; B₂(CO₃)₃
Explanation:
For names, carbonide does not exist; that rules out the first option. Carbide refers to just a carbon atom, not carbon and oxygen as in the polyatomic ion carbonate. That rids us of the third option. We are left with boron carbonate with the formula BCO or boron carbonate with the formula B₂(CO₃)₃.
Recall the carbonate polyatomic ion's formula: CO₃²⁻
Thus BCO cannot be the formula.
Option 4 is your answer, Boron Carbonate; B₂(CO₃)₃.
To further check your answer, observe the oxidation states of boron and the polyatomic ion carbonate. Boron can exist in oxidation states of either 2+ or 3+, and carbonate is only 2-; in this formula, boron will exhibit a 3+ state to balance out with carbonate.
2x3+ = 6+; 3x2- = 6-
6+ + 6- = 0; balanced
Answer: C. Adding concentrated HCL(aq)
Explanation:
HCl is an efficient acid that will increase the quantity of H+ in the solution and thus reduce the ionizing percentage of Ch3CO2H. The amount of ionization of the latter would be reduced by the addition of strong acid to a solution of weak acid.
The metallic bond between gold atoms makes it possible to create extremely thin sheets.
Atoms of the same element or atoms from different elements can form three types of bonds:
- Covalent bonds.
- Ionic bonds.
- Metallic bonds.
In the case of metals such as gold, the most common type of bond is the metallic bond. This bond:
- Is a strong bond.
- Involves the free movement of electrons between atoms.
- Makes metals highly malleable.
These characteristics explain the reason why it is possible to create extremely thin sheets as the material will not easily break due to the strong attraction between the atoms.
Learn more about atoms in: brainly.com/question/13981855
A balanced chemical equation can provide the following information : The reactants and products through their symbols and formulae. The ratio of molecules of reactants and products. As molecular masses are expressed in unified mass (u), the relative masses of reactants and products are known from the equation.
