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3 years ago

Why is the cellulose part of human diet

Chemistry

1 answer:

Luden [163]3 years ago

4 0

Answer:

Cellulose stimulates the work of intestines and increases their discharge.

Explanation:

Cellulose is a polysaccharide made of glucose polymers, which build plant fibers. Because of this, the plants possess their firmness.

Humans do not digest cellulose because they do not possess certain enzymes, but it is useful for their digestion because it stimulates the work of the intestines.

Cellulose enhances intestinal peristalsis. Peristalsis is series of contractions that allow the progressive movement of food through the digestive tract.

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6mole of H2O contains 18×6 g=108 g

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What would happen if there were no neutrons in an atom?

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3 years ago

A sealed container at 25oC contains a gas at a pressure of 104 kPa. What is the pressure of the gas when it is heated to 225oC?

seropon [69]

Answer:

174 kPa

Explanation:

Given that,

Initial temperature, T₁ = 25° C = 25+273 = 298 K

Final temperature, T₂ = 225°C = 225 + 273 = 498 K

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$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

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3 years ago

During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2

ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol = 12.81 grams

Step 6: Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = 75.70 grams CO2

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = 34.29 grams

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Why is the cellulose part of human diet​

Why is the cellulose part of human diet