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babunello [35]
3 years ago
15

Why is the cellulose part of human diet​

Chemistry
1 answer:
Luden [163]3 years ago
4 0

Answer:

Cellulose stimulates the work of intestines and increases their discharge.

Explanation:

Cellulose is a polysaccharide made of glucose polymers, which build plant fibers. Because of this, the plants possess their firmness.

Humans do not digest cellulose because they do not possess certain enzymes, but it is useful for their digestion because it stimulates the work of the intestines.

Cellulose enhances intestinal peristalsis. Peristalsis is series of contractions that allow the progressive movement of food through the digestive tract.

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in the following balanced equation 2C2H6 + 7O2 --> 4CO2 + 6H20 if 7.0 g of C2H6 react with 18g of O2, how many grams of water
lesya692 [45]

<u>Answer:</u> Amount of water produced is 8.6778 grams.

<u>Explanation:</u>

To calculate the amount of water produced, we first need to find the limiting reagent and for it we need to find the number of moles. To calculate the moles, we use the following equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ...(1)

  • Moles of C_2H_6:

Given mass of C_2H_6 = 7 grams

Molar mass of C_2H_6 = 30 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{7g}{30g/mol}=0.2333moles

  • Moles of O_2:

Given mass of O_2 = 18 grams

Molar mass of O_2 = 32 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{18g}{32g/mol}=0.5625moles

For the given chemical reaction, the equation follows:

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

By Stoichiometry:

7 moles of oxygen reacts with 2 moles of ethane.

So, 0.0261 moles of lead nitrate are produced by = \frac{2}{7}\times 0.5625=0.1607moles of ethane.

As, the required amount of ethane is less than the given amount. Hence, it is considered as the excess reagent.

Oxygen gas is considered as a limiting reagent because it limits the formation of product.  

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 6 moles of water.

So, 0.5625 moles of oxygen gas will produce = \frac{6}{7}\times 0.5625=0.4821moles of water.

  • Now, to calculate the mass of water produced, we use equation 1.

Molar mass of water = 18 g/mol

Moles of water produced = 0.4821 moles

Putting values in the equation, we get:

0.4821mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 8.6778 grams.

Hence, amount of water produced is 8.6778 grams.

8 0
4 years ago
If 11.9 kJ are used to heat a sample of water the temperature increases from 20.0°C to
Kipish [7]

Answer:

m=4.51g

Explanation:

Hello!

In this case, since the energy involved during a heating process is shown below:

Q=mCp\Delta T

Whereas the specific heat of water is 4.184 J/(g°C), we can compute the heated mass of water by the addition of 11.9 kJ (11900 J) of heat as shown below:

m=\frac{Q}{Cp\Delta T}

Thus, by plugging in, we obtain:

m=\frac{11900J}{4.184\frac{J}{g\°C}(650\°C-20.0\°C)}\\\\m=4.51g

Best regards!

7 0
3 years ago
Arrangement of small particles in substance is​
Flauer [41]

Answer:

The particle model represents particles by small, solid spheres.It describes the arrangement, movement and energy of particles in a substance. The model can be used to explain the physical properties of solids, liquids and gases.

5 0
4 years ago
Read 2 more answers
A mixture containing nitrogen and hydrogen weighs 3.48 g and occupies a volume of 7.47 L at 296 K and 1.02 atm. Calculate the ma
Sonbull [250]

Answer:

there is 2% of hydrogen and 98% of nitrogen (mass percent)

Explanation:

assuming ideal gas behaviour

P*V=n*R*T

n= P*V/(R*T)

where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)

thus

n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles

since the number of moles is related with the mass m through the molecular weight M

n=m/M

thus denoting 1 as hydrogen and 2 as nitrogen

m₁+m₂ = mt (total mass)

m₁/M₁+m₂/M₂ = n

dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁

w₁/M₁+w₂/M₂ = n/mt

w₁/M₁+(1-w₁) /M₂ = n/mt

w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂)

replacing values

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)

and w₂= 1-w₁= 0.98 (98%)

thus there is 2% of hydrogen and 98% of nitrogen

4 0
3 years ago
How to purify ammonia​
padilas [110]
In order to purify ammonia to high purity, two basic methods are used. The older one consists in passing gaseous ammonia containing 80 ppm of impurities under atmospheric pressure through liquid ammonia with dissolved metallic sodium.
5 0
3 years ago
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