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Nastasia [14]
3 years ago
7

What parts are present in every chemical equation?

Chemistry
1 answer:
77julia77 [94]3 years ago
3 0
I believe it’s

The reactants

The products

And the Arrow indicating the direction of the chemical reaction
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Redox reactions- does anyone know the answers?
Novay_Z [31]
Redox is a type of chemical reaction in which the oxidation states of atoms are changed. Redox reactions are characterized by the actual or formal transfer of electrons between chemical species, most often with one species undergoing oxidation while another species undergoes reduction.
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) Consider the starting materials and reagents. What do you expect to happen at the beginning of this reaction (Boxes 1-3 on the
tekilochka [14]

Answer:

Check the explanation

Explanation:

functional group found in the major organic product = alpha -beta unsaturated ketone

Reaction used to form this functional group = Michael condensation reaction

Also other reactions are - Aldol condensation , Robinson annulation reaction.

Kindly check the attached image below to see the step by step solution to the question above.

3 0
3 years ago
If you remove two protons and two neutrons from a gold atom (au), what new element is formed (if any)?
ivanzaharov [21]

Answer: Iridium

Explanation:

The atomic number of Iridium is 77.

8 0
2 years ago
Which element below is the most reactive?
const2013 [10]

Answer: Chlorine

Explanation: Chlorine has an atomic number of 17 and a configuration of 2, 8, 7. In the outermost shell, it has 7 seven electrons which means that it needs just one more electron to attain an octet configuration in that shell. Therefore it's can react quickly with any nearby nucleophile. Chlorine is more stable as a molecule (Cl2) because that way, it's in a covalent bond with itself and each chlorine atom in the molecule attains an octet. It's is also more stable as a Chloride ion (Cl-). Yes, Hydrogen (H) has a single electron in it's single shell and requires just one electron to attain a stable duplet configuration but it's not as reactive as the Cl because that single electron is closer to the nucleus and it's held firmly by the nuclear charge preventing it from being highly reactive. Unlike hydrogen, chlorine atom has 2 more shells shielding the outermost shell from the effect of the nuclear charge, hence, it's willing to accept electron from a donor. Oxygen need 2 more electrons to attain an octet in it's outermost shell considering it's configuration of 2,6. But in the presence of electrons, Cl would pick up electron faster than Oxygen since it requires just one. Neon on the other hand is a noble gas. It's shells are completely filled. considering it's configuration of 2,8, it has no space to accept electrons and cannot donate either. Hence, no room for reactivity.

8 0
3 years ago
Read 2 more answers
If 27.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 32.40 mL of 0.185 M HCl, what is the concentration of the
zhannawk [14.2K]

Given information : Volume of HCl = 32.40 mL

32.40 mL\times \frac{1 L}{1000 mL}

Volume of HCl = 0.0324 L

Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)

Volume of Ca(OH)2 = 27.0 mL

27.0 mL\times \frac{1 L}{1000 mL}

Volume of Ca(OH)2 = 0.027 L

We need to find the concentration of Ca(OH)2.

To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.

Step 1 : Find the moles of HCl using its given volume and concentration.

Moles = Concentration \times Volume in L

Moles = 0.185\frac{mol}{1L}\times 0.0324 L

Moles of HCl = 0.005994 mol HCl

Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.

Mole ratio are the coefficient present in front of the compound in a balanced equation.

Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)

(0.005994 mol HCl)\times \frac{(1 mol Ca(OH)2)}{(2 mol HCl)}

Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2

Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L

Concentration (Molarity) = \frac{(0.002997 mol)}{(0.027 L)}

Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M


4 0
4 years ago
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