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Pepsi [2]
2 years ago
9

It takes 945./kJmol to break a nitrogen-nitrogen triple bond. Calculate the maximum wavelength of light for which a nitrogen-nit

rogen triple bond could be broken by absorbing a single photon. Round your answer to 3 significant digits.
Chemistry
1 answer:
lesantik [10]2 years ago
8 0

Answer:

12.4 * 10^-8 m or 1.24 * 10^--7 m or 124 nm

Explanation:

We have to obtain the energy of the N≡N triple bond in joules as follows;

E = 945 * 1000/6.02 * 10^23 = 9.45 * 10^5/6.02 * 10^23

E = 1.6 * 10^-18 J

But;

E = hc/λ

h = Planks constant

c = speed of light

λ = wavelength of light

λ = hc/E

λ= 6.6 * 10^-34 * 3 * 10^8/1.6 * 10^-18

λ = 12.4 * 10^-8 m or 1.24 * 10^--7 m or  124 nm

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2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the
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Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball  = 10kg

Height of the rail  = 20m

Unknown:

Velocity at the bottom of the rail  = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

   V²   = U²  + 2gH

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3 0
3 years ago
A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak
baherus [9]

Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

<em>Where V is volume and n moles of 1, initial state and 2, final state of the gas</em>

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>
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2 years ago
How can i determin the size of my car
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Answer:

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