Answer:
Step-by-step explanation:
<u>Area of a Rectangle</u>
Given a rectangle of width W and length L, its area can be calculated with the formula:
A = WL
We are given the length of a rectangle is L=x and the width is W=x+10, thus the area is:
Multiplying:
Answer:
Step-by-step explanation:
All vertices meet at right angles, so sealing off these two rectangles will give you this:
![\displaystyle [2][4] + [4][8] = 8 + 32 = 40; 40mm.^2 \\ 4 + 6 + 2 + 4 + 8 + 8 = 32; 32mm.](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B2%5D%5B4%5D%20%2B%20%5B4%5D%5B8%5D%20%3D%208%20%2B%2032%20%3D%2040%3B%2040mm.%5E2%20%5C%5C%204%20%2B%206%20%2B%202%20%2B%204%20%2B%208%20%2B%208%20%3D%2032%3B%2032mm.)
* The missing sides are 4 and 6.
I am joyous to assist you anytime.
Answer:
25÷2(4+6)-4
Step-by-step explanation:
Parenthesis, multiplication, division, addition, and subtraction
When f(x) = 5, the x value for that would be 1.
Part 1) <span>Create a diagram that shows Kamila’s rectangular lawn and the gravel border. Assign variables to any unknown sides and label the diagram
see the attached figure
Part 2)</span><span>Use your diagram to determine how many square feet of the gravel border will surround the lawn
area of the border=[162*92]-[150*80]----> 14904-12000-----> 2904 ft</span>²
Part 3) <span>Kamila decided that the depth of the gravel needs to be 2 inches. What is the total volume of gravel needed for the border?
we know that
1 ft-------> 12 in
x--------> 2 in
x=2/12------> x=0.17 ft
volume of gravel needed=area of the border*deep of the gravel
</span>volume of gravel needed=2904*0.17----> 493.68 ft³
<span>
Part 4)</span><span>A large bag of colored rock contains a cubic yard and costs $30. What is the total cost of the rocks needed for the border?
</span>
1 yd³--------> 27 ft³
x---------> 493.68 ft³
x=493.68/27-----> 18.28 yd³
if 1 yd³----------> cost $30
18.28 yd³------> x
x=18.28*30------> x=$548.53
the answer Part 4) is $548.53
