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Komok [63]
3 years ago
12

To fit between two windows the width of a bookshelf must be no greater than 6 1/2 feet Mrs Aguilar purchases a bookshelf that is

77 inches wide which statement doescribes the relationship between the width of the bookshelf and and the distance between the windows
Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Given that

The width of a bookshelf must be no greater than 6 1/2 feet.

And a bookshelf that is 77 inches wide.

Since i ft = 12 inches

So 6.5 feet = 6.5×12 = 78 inches

So 78 inches > 77 inches

So the difference is 1 inch.

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An 18 fluid ounces bottle of lotion costs $10.99, what is the prices per fluid ounce?
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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

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3 years ago
Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!
SVEN [57.7K]
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Add all of them up and then divide by 10.
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Can someone answer this please
yanalaym [24]

Answer:

x=7

Step-by-step explanation:

8x-5y=16

8x-40=16

8x=56

x=7

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3 years ago
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