The relationship between portable electric tool and portable battery tool
1 answer:
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Answer:
A) 588 pounds
Explanation:
According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.
Referring the schematic:
<u>Moment about any point will be zero in equilibrium condition. </u>
∴Take moment about point L
Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N