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spayn [35]
3 years ago
5

What is the force required to produce a 1.4 Nm torque when applied to a door at a 60.0º angle and 0.40 m from the hinge?

Physics
1 answer:
Marysya12 [62]3 years ago
5 0
Refer to the diagram shown below.

The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N

Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m

This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N

Answer: 4.04 N

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7 0
3 years ago
Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are
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Answer:

The final temperature of the two objects is the same.

Explanation:

The expression for the heat energy in terms of mass, specific heat and the change in the temperature is as follows:

Q=mc(T_{f} -T_{i})

Here, Q is the heat energy, m is the mass of the object, c is the specific heat and T_{f},T_{i} are the final temperature and initial temperature.

According to the given question, Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are added to each object.

Q=mc(T_{f}-T_{i})                                             ............(1)

Q=mc(T'_{f}-T_{i})                                            .............(2)

From (1) and (2),

mc(T_{f}-T_{i})=mc(T'_{f}-T_{i})

T_{f}-T_{i}=T'_{f}-T_{i}

T_{f}=T'_{f}

Therefore, the final temperature of the two objects is the same.

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