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Maru [420]
3 years ago
14

While researching scuba diving, Pablo reads how hot a tank should get while being filled with air. Which law best explains why t

he scuba tank would heat up?
Gay-Lussac’s law, because as the pressure decreases, the temperature increases

Gay-Lussac’s law, because as the pressure increases, the temperature increases

Boyle’s law, because as the volume decreases, the temperature increases

Boyle’s law, because as the pressure increases, the temperature increases​
Physics
2 answers:
dedylja [7]3 years ago
9 0

Answer:

Gay-Lussac’s law, because as the pressure increases, the temperature increases

Explanation:

I just took the test on Edgenuity.

I hope this helps!

Lady_Fox [76]3 years ago
5 0

Answer:

Gay-Lussac’s law, because as the pressure increases, the temperature increases

Explanation:

First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.

This means that in this situation we can apply Gay-Lussac's law, which states that:

"for a gas kept at constant volume, the pressure of the gas is proportional to the absolute temperature of the gas".

Mathematically:

p\propto T

where p is the pressure in Pascal and T is the temperature in Kelvin.

In this case, the tank is filled with air: this means that the pressure of the gas inside the tank increases. And therefore, according to Gay-Lussac's law, the temperature will increase proportionally, and this explains why the tank gets hot.

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If your asking about the total amount of time the sun is visible, it will be equal over the course of a year. In Nome, Alaska, it will be daylight almost 24 hours a day in the summer and be dark almost 24 hours a day in the winter. In San Diego they are much closer to the equator and will receive sunlight roughly the same amount each day all year long. In the end these times will add up to the same amount.

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OLEGan [10]

Answer:

C = 771.35 J/kg°C

Explanation:

Here, e consider the conservation of energy equation. The conservation of energy principle states that:

Heat Given by Metal Piece = Heat Absorbed by Water + Heat Absorbed by Container

Since,

Heat Given or Absorbed by a material = m C ΔT

Therefore,

m₁CΔT₁ = m₂CΔT₂ + m₃C₃ΔT₃

where,

m₁ = Mass of Metal Piece = 2.3 kg

C = Specific Heat of Metal = ?

ΔT₁ = Change in temperature of metal piece = 165°C - 18°C = 147°C

m₂ = Mass of Metal Container = 3.8 kg

ΔT₂ = Change in temperature of metal piece = 18°C - 15°C = 3°C

m₃ = Mass of Water = 20 kg

C₃ = Specific Heat of Water = 4200 J/kg°C

ΔT₃ = Change in temperature of water = 18°C - 15°C = 3°C

Therefore,

(2.3 kg)(C)(147°C) = (3.8 kg)(C)(3°C) + (20 kg)(4186 J/kg°C)(3°C)

C[(2.3 kg)(147°C) - (3.8 kg)(3°C)] = 252000 J

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