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Sveta_85 [38]
3 years ago
14

Pentagon ABCDE and pentagon A"B"C"D"E" are shown on the coordinate plane below:

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

(x+8, y+2) and reflect across x axis

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Cos (-Ø)= √3/3 sinØ <0 what is the value of sinØ?
Inga [223]

Answer:

sin∅= - √6/3

Step-by-step explanation:

Trigonometric function cos is even function which mean:

cos (-∅) = cos ∅

Trigonometric function sin is odd function which mean:

sin (-∅) = - sin∅  => sin∅ < 0

The basic trigonometric equation reads in this case with angle marked ∅:

sin²∅ + cos²∅ = 1  => sin²∅ = 1 - cos²∅ => sin²∅ = 1 - ( √3/3 )² =>

sin²∅ = 1 - (3/9) => sin²∅ = 1 - (1/3) = (3/3) - (1/3) = 2/3 => sin∅ = - √(2/3) =>

sin∅ = - √2/√3 => sin∅ = - √6/3

God with you!!!


3 0
3 years ago
What is the area of this figure. <br><br><br> 128 in<br> 136 in<br> 153 in<br> 258 in
aliya0001 [1]
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
6 0
3 years ago
In the pictures down below<br><br>Can anyone help? Fractions and percents<br><br> 
wariber [46]
1st Picture:
3)- \frac{6}{7} +\frac {10}{11}&#10;\\\\LCD:77&#10;\\\\\frac{6}{7}* \frac{11}{11} +  \frac{10}{11}*\frac{7}{7}= \frac{66}{77} + \frac{70}{77}  = \frac{136}{77} = 1\frac{59}{77} &#10; \\  \\ 4) 3\frac{6}{7}* 2 \frac{1}{10}=  \frac{27}{7} * \frac{21}{10} = \frac{567}{70} =\frac{81}{10} = 8\frac{1}{10}&#10;\\\\5)2\frac{1}{2}+3\frac{1}{3}&#10;\\\\LCD: 6&#10;\\\\ 2\frac{3}{6} + 3\frac{2}{6} =5\frac{5}{6}&#10;\\\\6)5\frac{1}{8}*-6\frac{6}{11}=\frac{41}{8}* \frac{72}{11}=\frac{2952}{88}=\frac{369}{11}=33\frac{6}{11}

2nd Picture:

1)80 percent of 80 = .8*80 =64&#10;\\\boxed{64}&#10;\\\\2)95percent of 100=.95*100=95&#10;\\\boxed{95}
7 0
3 years ago
F(5)=3x+2 <br> What is the solution
Nady [450]

Answer:

f=3/5x+2/5c

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Jose stores his baseball cards in a box like the one shown
TEA [102]
The formula for volume (V) is <em>l * w * h</em>, where <em>l</em> is length, <em>w</em> is width, and <em>h</em> is height. So in a sense, we have already solved the first part of this problem!

V = 10 * 8 * 3

Now, all we have to do is complete this equation to find the volume.

10 * 8 = 80

80 * 3 = 240

The volume of Jose's box for baseball cards is 240 cubic inches.
Hope that helped! =)
7 0
4 years ago
Read 2 more answers
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