Answer:
Given:
Mass of elephant = 5240 kg
The initial speed of the elephant = 4.55 m/s
Mass of the rubber ball, m, = 0.15 kg
Inital speed of the rubber ball, v = 7.81 m/s
On substitution in 
= ![[\frac{2m_{1} }{m_{1} +m_{2} } ]V_{1f}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2m_%7B1%7D%20%7D%7Bm_%7B1%7D%20%2Bm_%7B2%7D%20%7D%20%5DV_%7B1f%7D)
+ ![[\frac{m_{2}-m_{1}}{m_{1}+m_{2} } ] v_{2f}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bm_%7B2%7D-m_%7B1%7D%7D%7Bm_%7B1%7D%2Bm_%7B2%7D%20%20%7D%20%5D%20v_%7B2f%7D)
= ](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2%2A5240_%7B%7D%20%7D%7B5240_%7B%7D%20%2B0.15_%7B%7D%20%7D%20%5D%28-4.55_%7B%7D%29)
+ ![[\frac{0.15_{}-5240_{}}{5240_{}+0.15_{} } ] (7.81_{})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B0.15_%7B%7D-5240_%7B%7D%7D%7B5240_%7B%7D%2B0.15_%7B%7D%20%20%7D%20%5D%20%287.81_%7B%7D%29)
a) The negatıve sign shows that the ball bounces back in the direction opposite to the incident
b) it is clear that the velocity of the ball increases and therefore it is kinetic energy
. The ball gains kinetic energy from the elephant.
Answer:
0.05 m
Explanation:
From the question given above, the following data were obtained:
Mass of first object (M1) = 9900 kg
Gravitational force (F) = 12 N
Mass of second object (M2) = 52000 kg
Distance apart (r) =?
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Thus, we can obtain the distance between the two objects as shown below:
F = GM1M2/r²
12 = 6.67×10¯¹¹ × 9900 × 52000 /r²
Cross multiply
12 × r² = 6.67×10¯¹¹ × 9900 × 52000
Divide both side by 12
r² = (6.67×10¯¹¹ × 9900 × 52000)/12
Take the square root of both side
r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]
r = 0.05 m
Therefore, the distance between the two objects is 0.05 m
<span>Everything in the system is stable and therefore the objects motion is stable. That is to say it is not changing what it is already doing. As far as i know zero times zero is still zero. In that case then the motion must be constant or stable.</span>
<span>Protozoa live in seas, rivers, lakes, ponds, decaying matters and soil</span>
Answer:
C
Explanation:
When trash accumulates, astronauts manually squeeze it into trash bags, temporarily storing almost two metric tons of it for relatively short durations, and then send it away in a departing commercial supply vehicle, which either returns it to Earth or incinerates it during reentry through the atmosphere.
