Answer:
photosynthesis, burning fossil fuels, and simply releasing breath from the lungs.
Answer:
9.51
Explanation:
The distance s is given by:

The change in distance is given by the time derivative of s:

For the time t you solve the equation of distance x for time:

Plugging in for t:

Answer:
Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.
Explanation:
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Answer: Glaciers
Water near the poles would most likely be stored as glaciers. Glaciers are slow moving rivers that are a buildup of ice and snow.
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The near-point distance of the eye is 11 cm.
<h3>What is the eye's near-point distance?</h3>
The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.
The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:
1/f = 1/v + 1/u
where;
f = focal length
v = image distance
u = object distance
From the data provided;
f = 2.20 cm
v = 2.75 cm
u = ?
Solving for u:
1/u = 1/f - 1/v
1/u = 1/2.20 - 1/2.75
1/u = 0.91
u = 11 cm
In conclusion, the lens formula is used to determine the eye's near-point distance.
Learn more about eye's near-point distance at: brainly.com/question/16391605
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