First covert them to fractions with the same denominator so you can compare them (9/12 and 4/12), then subtract the numerators, and not the denominators (9/12-4/12), then whatever you get is the answer (5/12). If you can, simplify.

7 0

3 years ago

Read 2 more answers

For a cube whose side length the lexpression

AleksandrR [38]

Can you give more information?

7 0

2 years ago

What is the general process for solving an equation with one variable?

elena55 [62]

Greetings!

"What is the general process for solving an equation with one variable?"...

Typically when solving an equation with one variable, your objective is to isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.

Example:
 $2x+4=64$
Add -4 to both sides to isolate the variable.
 $(2x+4)+(-4)=(64)+(-4)$ 
Simplify.
 $2x=60$
Divide both sides by 2 to isolate the variable on one side.
$(2x)/2=(60)/2$
$x=30$

Hope this helps.
-Benjamin

5 0

3 years ago

Solve the equation cot 2x + cot x =3

rusak2 [61]

tan2x*cotx - 3 = 0

We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx

==> sin2x/cos2x *cosx/sinx = 3

Now we know that sin2x = 2sinx*cosx

==> 2sinxcosx/cos2x * cosx/sinx = 3

Reduce sinx:

==> 2cos^2 x/ cos2x = 3

Now we know that cos2x = 2cos^2 x-1

==> 2cos^2 x/(2cos^2 x -1) = 3

==> 2cos^2 x = 3(2cos^2 x -1)

==> 2cos^2 x = 6cos^2 x - 3

==> -4cos^2 x= -3

==> 4cos^2 x = 3

==> cos^2 x = 3/4

==> cosx = +-sqrt3/ 2

==> x = pi/6, 5pi/6, 7pi/6, and 11pi/6

3 0

3 years ago