Using substitution:
13(y+6)-6y=22
13y+78-6y=22
7y+78=22
/// -78 -78
7y=-56
÷7 ÷7
y=-8
x=y+6
x=-8+6
x=-2
So, x equals -2 and y equals -8.
Given:
Sum of two consecutive integers is 325.
To find:
The number that is the least of the two consecutive integers.
Solution:
Let the two consecutive integers are x and x+1. So,
Subtract 1 from both sides.
Divide both sides by 2.
The second integer is
Since , therefore, the least of the two consecutive integers is 162.
Answer:
$72.08
Step-by-step explanation:
10*8=80
(80×15%)×6%=72.08
5.
Let x be the age of the father and y be the age of the son. As of today, he's 3 times older, so we have
10 years ago their ages were, respectively, x-10 and y-10, and the father was 5 times older:
So, we have the system
Using the first equation, we can substitute every occurrence of "x" with "3y" in the second equation:
So, the son is 20 years old, which means that the father is 60 years old.
Indeed, 10 years ago they were 10 and 50 years old, so the father was 5 times older.
6.
Let x be the age of the grandfather and y the age of the granddaughter. We know that the grandfather is 10 times older:
He also is 54 years older:
Again, if we substitute x=10y in the second equation we have
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