Answer:
1) 
2) 
Explanation:
Given:
- mass of heavier student,
- mass of lighter student,
- velocity of the heavier student after the mutual push,
1)
Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.
Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.
2)
<u>From the condition of elastic collision:</u>
Answer:
1.33m/s²
Explanation:
Given parameters:
Initial velocity = 5m/s
Final velocity = 25m/s
Time taken = 15seconds
Unknown:
Acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time.
Acceleration = 
v is the final velocity
u is the initial velocity
t is the time taken
So;
Acceleration = 
= 1.33m/s²
We know, Power = Voltage * Current
P = 660 * 12 = 7920 watt
In short, Your Answer would be Option A
Hope this helps!
Answer:
The magnitude of the average induced emf in the loop is 0.1 volts.
Explanation:
let Ф be the flux in the loop, B be the magnetic field and A be the area of the loop.
the induced emf in the loop is given by:
ε = - dФ/dt
= - d(B×A)/dt
= - A×d(B)/dt
= - π×r^2×d(B)/dt
= - π×(0.40)^2×(0.20 - (-0.30))/(2.5 - 0)
= 0.1 volt
Therefore, the magnitude of the average induced emf in the loop is 0.1 volts.
B) O False because that’s just what I wanted to put that’s what I think the answer is
