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SSSSS [86.1K]
3 years ago
9

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi

mately 98 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 61 bpm. What is the average force exerted by the blood on the wall of the aorta.
Physics
1 answer:
Alisiya [41]3 years ago
8 0

Answer:

The force is F = 0.1441 \  N

Explanation:

From the question we are told that

   The volume of blood ejected is  V_b  =  65cm^3 = 65*10^{-6} \  m^3

    The velocity of the ejected blood is  v  = 98 cm/ s = 0.98 \  m/s

    The mass density of blood is  \rho = 1060 \  kg/m^3

    The heart rate is  R  =  61 bpm(beats \  per \  miunite) = \frac{61}{60} = 1.0667\  bps

Generally the average force exerted is mathematically represented as

     F = 2 *  \rho *  V_b *  R *  v

=>   F = 2 * 1060  *  (65*10^{-6}) *1.0667   *   0.98

=>   F = 0.1441 \  N    

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