Question

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 98 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 61 bpm. What is the average force exerted by the blood on the wall of the aorta.

Answer 1

Answer:

The force is $F = 0.1441 \ N$

Explanation:

From the question we are told that

   The volume of blood ejected is  $V_b = 65cm^3 = 65*10^{-6} \ m^3$

    The velocity of the ejected blood is  $v = 98 cm/ s = 0.98 \ m/s$

    The mass density of blood is  $\rho = 1060 \ kg/m^3$

    The heart rate is  $R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps$

Generally the average force exerted is mathematically represented as

     $F = 2 * \rho * V_b * R * v$

=>   $F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98$

=>   $F = 0.1441 \ N$