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Scorpion4ik [409]
3 years ago
6

Classify the real number Thank you so much❤❤❤

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
Rational and integer are the only two answers
vladimir2022 [97]3 years ago
6 0

I know for sure it's rational and an integer. I don't think there should be anymore to apply.

°.✩┈┈┈┈∘*┈┈୨♡୧┈┈*∘┈┈┈┈✩.°

I hope this helped you. .+(´^ω^`)+.

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Please include work
OLga [1]

Answer:

9.     6k + 5 and 2k - 1.

10.    5√2 .

Step-by-step explanation:

9.    Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10.  The ratio of a leg to the hypotenuse is  1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2  

= 10 √2  / 2

= 5√2 .

7 0
3 years ago
Which Venn diagram has shading that represents the union of set G and set I?<br> answer plslsls
Ad libitum [116K]

Answer:

  • B or the second diagram

Step-by-step explanation:

<u>The sets as per diagrams are as follows</u>

  • 1. Intersection of G and I
  • 2. Combination of G and I
  • 3. Combination of G and I excluding H
  • 4. Combination of G and I excluding common region

7 0
2 years ago
Which inequality does this graph represent?
lana [24]

Answer:

if the line counts then d if it doesnt then b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A 99% confidence interval for the sugar content (per 5 oz. serving) of a shipment of strawberries is 5.9 to 8.3 grams.
gavmur [86]

Answer:

Sample mean = 7.1

Margin of error = 0.465

Step-by-step explanation:

Formula for confidence interval is;

CI = x¯ ± zE

Where;

x¯ is sample mean

z is critical value at confidence level

E is margin of error.

z for 99% Cl is 2.58

We are told the CI is 5.9 to 8.3.

Thus;

5.9 = x¯ - 2.58E - - - - (1)

8.3 = x¯ + 2.58E - - - - (2)

Add both equations together to get;

14.2 = 2x¯

x¯ = 14.2/2

x¯ = 7.1

Put 7.1 for x¯ in eq 1 to get;

5.9 = 7.1 - 2.58E

7.1 - 5.9 = 2.58E

E = 1.2/2.58

E = 0.465

5 0
2 years ago
What is the solution of 3+x-2/x-3&lt;_4
VikaD [51]

Step-by-step explanation:

3+x-2/x-3<_4

cross multiply

3+x-2<_4(x-3)

3+x-2<_4x-12

1+x<_4x-12

collect like terms

1+12<_4x-x

13<_3x

divide both side by 3

13/3<_×

6.5<_x

3 0
2 years ago
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