Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that .
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
y + 3 = 10/11(x + 3)
Step-by-step explanation:
Given the points (-3, -3) and (8, 7), we can use these coordinates to solve for the slope of the line using the formula:
Let (x1, y1) = (-3, -3)
(x2, y2) = (8, 7)
Substitute these values into the slope formula:
Thus, slope (m) = 10/11.
Next, using the slope (m) = 10/11, and one of the given points (-3, -3), we'll substitute these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (-3, -3)
m = 10/11
y - y1 = m(x - x1)
y - (-3) = 10/11[x - (-3)]
Simplify:
y + 3 = 10/11(x + 3) this is the point-slope form.
