Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.

To find:
The theorem which shows that
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
5 m/s · 12 s = 5 m · 12 = 60 m
Answer: in 12 seconds that car has gone 60 metres.
Answer:
(7-5)
Step-by-step explanation:
According to PEMDAS, parenthesis go first. But there are two sets of parenthesis so the one inside the other goes first.
Next would be [3+(2*2)]
Then, [3+4]
Then, -8/1
Then, -3(7)
So the question would be 4-8-21
Which gives you -25 as an answer.
I realize that you weren't asking for the whole thing but maybe there are follow up questions.
Answer:
y + 3 = 10/11(x + 3)
Step-by-step explanation:
Given the points (-3, -3) and (8, 7), we can use these coordinates to solve for the slope of the line using the formula:

Let (x1, y1) = (-3, -3)
(x2, y2) = (8, 7)
Substitute these values into the slope formula:

Thus, slope (m) = 10/11.
Next, using the slope (m) = 10/11, and one of the given points (-3, -3), we'll substitute these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (-3, -3)
m = 10/11
y - y1 = m(x - x1)
y - (-3) = 10/11[x - (-3)]
Simplify:
y + 3 = 10/11(x + 3) this is the point-slope form.