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____ [38]
3 years ago
9

The quadrilateral obtained by joining the mid points of adjacent sides of a square is?​​

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

Square

Step-by-step explanation:

the quadrilateral obtained by joining the mid points of adjacent sides of a square is a square

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Rewrite the following expression using the properties of loy
Dimas [21]

\\ \rm\Rrightarrow log_2z+2log_2x+4log_9y+12log_9x-2log_2y

  • log_a^b=bloga
  • log_a(bc)=log_a b+log_a c

So

\\ \rm\Rrightarrow log_2z+log_2x^2-log_2y^2+log_9y^4+log_9x^{12}

\\ \rm\Rrightarrow log_2(zx^2)-log_2y^2+log_9(y^4x^{12})

\\ \rm\Rrightarrow log_2\left(\dfrac{zx^2}{y^2}\right)+log_9(y^4x^{12})

6 0
2 years ago
Read 2 more answers
The area of a triangle is 15 square inches
babunello [35]

Answer:

6 inches

Step-by-step explanation:

The formula for the area of a triangle is

Area = \frac{1}{2} (bh)

b - base

h - height

the first step is to add the information that we know into the formula.

We know the area = 15 inches^{2} and the height = 5 inches

15 in^{2} = \frac{1}{2} (b)(5)

if we had both the base and the height, the next step would be to multiply

b x h then half the answer to work out the area but as we already have the area (15in^{2}) we need to work in reverse.

15 x 2 = 30

what is 5 multiplied by to get 30?

5 x ? = 30

30 ÷ 5 = 6

∴ the base = 6inches

to check if our answer is correct, we can place these numbers into the formula

A = \frac{1}{2} (6)(5)

A = \frac{1}{2} (30)   (30 ÷ 2 = 15)

A = 15in^{2}

I hope this was helpful :-)

5 0
3 years ago
HELP PLS I DONT GET THIS WILL GIVE BRAINLIEST
kicyunya [14]

The triangles are the same

CA= 8.5

AT=5

DG=12

T=70

O=57

C=53

3 0
2 years ago
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10n^3-25n^2-16n+40 I'm so lost on this please help
Mariulka [41]
I think you're factoring this...? You can do that by grouping here.  Put the 4 terms in groups of 2 and factor out the greatest common factor. What's left behind is a common binomial factor that can also then be factored out. Like this:
(10 n^{3} -25 n^{2})-(16n+40)
Factoring what we can out of both sets gives us this:
5 n^{2} (2n-5)-8(2n-5)
The 2n-5 is a common factor between both the sets of terms, which in turn can also be factored out:
(2n-5)(5 n^{2}-8)
I'm not exactly sure what you are doing with this, but we can keep factoring for the sake of completeness.  The 5 n-squared term can also be factored:
5 n^{2}-8=0 and 5 n^{2} =8 and n^{2} = \frac{8}{5} so n= \frac{ \sqrt{8} }{ \sqrt{5} }.  Simplifying that down its simplest is this:
n=+/- \frac{2 \sqrt{10} }{5}
So your three factors for that polynomial are
(n- \frac{5}{2} ),(n- \frac{2 \sqrt{10} }{5} ),(n+ \frac{2 \sqrt{10} }{5} ),

6 0
3 years ago
Boris started to run on a treadmill after setting its timer for 92 minutes. The display says that he has finished 73% of his run
Tanzania [10]

Answer:

67 minutes

Step-by-step explanation:

7 0
2 years ago
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