Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
What's the point in all of the 11111?
Answer is: Reactants and products are written in words; reactants are on the left, products are on the right side of reaction.
For example, balanced chemical reaction for cellular respiration (convert biochemical energy):
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O or:
glucose + oxygen → carbon dioxide + water.
Glucose and oxygen are reactants and carbon dioxide and water are products of reaction.
This reaction is exothermic (energy is released).
Word equation is a chemical reaction expressed in words rather than chemical formulas.
