Simplify and write the answer in exponential form.

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

a

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

b

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

c

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

d

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

2 years ago

Which subsets does 65/13 belong? Move the appropriate subsets into this box.

zhannawk [14.2K]

Answer:

roam

Step-by-step explanation:

free points

3 0

2 years ago

Let i be the first of four consecutive integers. what is 3 less than the sum of those integers ?

Dmitrij [34]

The consecutive integers are i, i+1, i+2, i+3.

3 less than sum of the integers

= i + i +1 + i + 2 + i + 3 - 3 = 4i + 3

5 0

3 years ago

PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??

Umnica [9.8K]

$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$

3 0

2 years ago

Can someone please please help me with this I’m sooo confused

nexus9112 [7]

When it says x and y are directly related it means that x is multiplied by something to get y. To solve you divide y by x which is 840 divided by 6. Which is 140 then you multiply and solve so the y value for 5 is 700. The x value for 420 is 3 and the y value for 4 is 560.

7 0

2 years ago