Answer:
The velocity of the shell when the cannon is unbolted is 500.14 m/s
Explanation:
Given;
mass of cannon, m₁ = 6430 kg
mass of shell, m₂ = 73.8-kg
initial velocity of the shell, u₂ = 503 m/s
Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.
K.E = ¹/₂mv²
K.E = ¹/₂ (73.8)(503)²
K.E = 9336032.1 J
When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy
change in initial momentum = change in momentum after
0 = m₁u₁ - m₂u₂
m₁v₁ = m₂v₂
where;
v₁ is the final velocity of cannon
v₂ is the final velocity of shell
Apply the principle of conservation kinetic energy
Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s
It’s 10 joules. W=FD, W=5•2=10
Answer:
How does energy travel?
One way the energy can travel is through radiation. An object can radiate energy in the form of electromagnetic waves, for example when a strong light is turned on and you can feel some heat coming from it, or when you walk under the sunlight and you can feel the heat in your skin.
Where is the initial source of energy in our solar system?
In the solar system, the source of energy comes from the Sun, and the sun irradiates that energy to all the nearby objects.
What is the process that gives off energy from the sun called?
The process is called radiation, this is all the energy that comes from the sun in the form of different electromagnetic waves (light in the visible range, UV rays, etc...)
Light energy is converted to chemical energy during photosynthesis.
Answer:
7.6427m/s
Explanation:
Given:
#Applying the conservation of momentum along the x-axis:
#And along y-axis:
#Solving for 
:
#By substitution in the x-axis equation:
Hence the original speed of the ball before impact is 7.6427m/s
