Answer:
1.991 × 10^(8) N/m²
Explanation:
We are told that its volume increases by 9.05%.
Thus; (ΔV/V_o) = 9.05% = 0.0905
To find the force per unit area which is also pressure, we will use bulk modulus formula;
B = Δp(V_o/ΔV)
Making Δp the subject gives;
Δp = B(ΔV/V_o)
Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²
Thus;
Δp = 2.2 × 10^(9)[0.0905]
Δp = 1.991 × 10^(8) N/m²
The outward push of the core created by nuclear fusion and the inward pull of gravity from the core
Answer:768.75N
Explanation:
mass=62.5kg
acceleration=12.3m/s^2
Force=mass x acceleration
Force=62.5 x 12.3
Force=768.75N
Answer:
normal force = 10 N
Explanation:
Given data
frictional force = 0.400 N
coefficient of kinetic friction = 0.04
Solution
we get here normal force that is express as
normal force = ............1
put here value and we will get value
normal force =
solve it we get
normal force = 10 N
The answer is 0 , hope this helps