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3 years ago

Define newtons first law of motion with examples(class 9 ) plssss itz urgent

2 answers:

6 0

Newton's first law of motion states that an object maintains its state motion or that of rest unless subjected to some external force.

It means that if an object is moving then it will not stop until we apply force on it. Similarly, if an object is at rest, then it will not move until we apply force on it. Objects also maintain their speed, it means that their speed will not change unless we apply force.

This is because objects have inertia. Inertia is the measure of the property of the object to oppose any change in its motion. More the mass more the inertia. This is why this law is also known as the law of inertia.

Example:

1. A bag kept on the top of bus, falls backward because it maintains its state of rest and bus starts moving.

Akimi4 [234]3 years ago

5 0

<h3>Newtons first law state that if a body is in motion it will be in motion and if a body is in rest it will tend to be in rest. This phenomena is also called INERTIA. Example: We tend to fall sideways when a car turn suddenly</h3>

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Suppose you have a total charge qtot that you can split in any manner. Once split, the separation distance is fixed. How do you

dybincka [34]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know from the Coulomb's Law that, Coulomb's force is directly proportional to the product of two charges q1 and q2 and inversely proportional to the square of the radius between them.

So,

F = $\frac{Kq1q2}{r^{2} }$

Now, we are asked to get the greatest force. So, in order to do that, product of the charges must be greatest because the force and product of charges are directly proportional.

Let's suppose, q1 = q

So,

if q1 = q

then

q2 = Q-q

Product of Charges = q1 x q2

Now, it is:

Product of Charges = q x (Q-q)

So,

Product of Charges = qQ - $q^{2}$

And the expression qQ - $q^{2}$ is clearly a quadratic expression. And clearly its roots are 0 and Q.

So, the highest value of the quadratic equation will be surely at mid-point between the two roots 0 and Q.

So, the midpoint is:

q = $\frac{Q + 0}{2}$

q = Q/2 and it is the highest value of each charge in order to get the greatest force.

8 0

3 years ago

g A circular loop of wire with radius 3 m is flat on the xy plane in a magnetic field which is pointed in the z-direction and ha

Phantasy [73]

Answer:

emf=-0.035V

Explanation:

this problem can be solved with the Lenz's law:

$emf=-\frac{\Delta \Phi_{B}}{\Delta t}$

where PhiB is the magnetic flux. In this case we have

$\Delta \Phi_{B}=B(A_1-A_2)$

due to the magnetic field is constant. A is the area of the circular loop. Hence

$\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2$

Finally

$emf=-\frac{0.106Tm^2}{3s}=-0.035V$

HOPE THIS HELPS!!

7 0

3 years ago

How far does a car travel as it accelerates from rest to 24 m/s in 6 seconds?

____ [38]

Answer:

$\boxed{\sf Distance \ travelled = 72 \ m}$

Given:

Initial velocity (u) = 0 m/s (Starts from rest)

Final velocity (v) = 24 m/s

Time taken (t) = 6 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

$\boxed{ \bold{s = (\frac{v + u}{2} )t}}$

By substituting value of v, u & t in the equation we get:

$\sf \implies s = ( \frac{24 + 0}{2} ) \times 6 \\ \\ \sf \implies s = \frac{24}{2} \times 6 \\ \\ \sf \implies s = 12 \times 6 \\ \\ \sf \implies s = 72 \: m$

$\therefore$

Distance travelled by car (s) = 72 m

7 0

4 years ago

Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then h

Shalnov [3]

The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3

Thus, the distance that the effort must move will be 1/3 inch

5 0

4 years ago

Read 2 more answers

Is playing baseball work

Arisa [49]

Answer:

Depends

Explanation:

If you play baseball on a team then yes if you don't and you play on your free time then no it isn't work because your doing it for fun now if you do it on a team then you are working with your team and winning as a team

8 0

3 years ago