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Travka [436]
3 years ago
6

What’s the velocity of the rocket? Use .

Physics
2 answers:
Black_prince [1.1K]3 years ago
7 0

Answer:

25 m/s

Explanation:

Lostsunrise [7]3 years ago
3 0

<u>Explanation</u>:

Consider the given function  K(t)=\frac{1}{2} m(t) \cdot v(t)^{2}

Given that the velocity of rocket is increases at the rate of 15 m / \sec ^{2} \text { Hence } \frac{d v}{d t}=15

The mass of rocket is decreasing at rate of 10 \mathrm{kg} / \mathrm{sec}.

Hence \frac{d m(t)}{d t}=-10

Now find the rate of change of kinetic energy when m(t)=2000 \mathrm{kg}=2 \times 10^{3} \mathrm{kg}and v(t)=5000 m / \mathrm{sec}^{2}=5 \times 10^{3} \mathrm{m} / \mathrm{sec}^{2}

Now consider the given equation,

\begin{aligned}&K(t)=\frac{1}{2} m(t) \cdot v(t)^{2}\\&\frac{d K}{d t}=\frac{1}{2}\left[m(t) \times 2 v(t) \times \frac{d v(t)}{d t}+v(t)^{2} \frac{d m}{d t}\right]\end{aligned}

Now substituting the values m(t)=2000 k g=2 \times 10^{3} k g and v(t)=5000 m / \mathrm{sec}^{2}=5 \times 10^{3} \mathrm{m} / \mathrm{sec}^{2}

\begin{aligned}\frac{d K}{d t} &=\frac{1}{2}\left[2 \times 10^{3} \times 2 \times 5 \times 10^{3} \times 15+\left(5 \times 10^{3}\right)^{2}(-10)\right] \\&=\frac{1}{2}\left[300 \times 10^{6}+(-250) \times 10^{6}\right] \\&=\frac{1}{2}\left[(50) \times 10^{6}\right] \\&=25 M J\end{aligned}

The rate at which kinetic energy changing is 25MJ

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How can the potential energy in magnets be used to create kinetic energy in an object without making contact?
NemiM [27]

Answer:  If you move a magnet quickly through a coil of copper wire, the electrons will move - this produces electricity.

Explanation:

7 0
3 years ago
A wrench 20 cm long lies along the positive y-axis and grips a bolt at the origin. A force is applied in the direction 0, 4, −3
Andreyy89

Answer:

1250 N

Explanation:

length of wrench = 20 cm = 0.2 m

Write the length of wrench in vector form

r = 0.2 j metre

Direction of force= \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

Let the magnitude of force is F

So, write the force in vector form

F = F  \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

torque, T = 150 Nm

Torque = T = r x F

150 i =0.2j\times F\frac{0i+4j-3k}{5}

F = 1250 N

Thus, the magnitude of force is 1250 N.

6 0
3 years ago
The inductive reactance of the circuit is exactly twice the resistance: XL=2R. Adjust the phasor that represents the voltage acr
SVETLANKA909090 [29]

Answer:

∅=63.43^{0}

Explanation:

z=impedance

x_{l}=2R

R=R

The resultant of the resistances in the circuit is called impedance

x_{l} is inductive reactance of the circuit

R is the resistance of the resistor

z=\sqrt{xl^{2}+R^2 }

z=\sqrt{2R^{2}+R^2 }

Z=\sqrt{5R^2}

Z=R\sqrt{5}ohms

tan∅=2R/R

tan∅=2

∅=Tan^-1(2)

∅=63.43^{0}

phase angle is ∅=63.43^{0}

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3 years ago
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Answer:

1)A

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5 0
2 years ago
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
konstantin123 [22]

Answer:

I=2.71\times 10^{-5}\ A

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.  

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}, r is radius

Let I is the displacement current. It is given by :

I=C\dfrac{dV}{dt}

Here, \dfrac{dV}{dt} is rate of increasing potential difference

So

I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A

So, the value of displacement current is 2.71\times 10^{-5}\ A.

4 0
3 years ago
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