Answer:
Explanation:
The centripetal acceleration is expressed as;
a = v²/r
a is the acceleration = 50m/s²
v is the velocity = 10m/s
r is the radius
To get the radius
r = v²/a
r = 10²/50
r = 100/50
r = 2m
Hence its radius is 2m
The work done to push the refrigerator is 500 Nm.
Explanation:
Work done is the measure of force required to move any object from one point to another. So it is calculated as the product of force and displacement.
If the force increases the work done will increase and similarly, the increase in displacement increases the work done. So to push the refrigerator work should be done on the object and not by the object.
As the force is 100 N and the displacement is 5 m then, work done can be measured as
Work = Force × Displacement
Work = 100 × 5 = 500 Nm
So the work done to push the refrigerator is 500 Nm.
Answer:
required distance is 233.35 m
Explanation:
Given the data in the question;
Sound intensity
= 1.62 × 10⁻⁶ W/m²
distance r = 165 m
at what distance from the explosion is the sound intensity half this value?
we know that;
Sound intensity
is proportional to 1/(distance)²
i.e
∝ 1/r²
Now, let r² be the distance where sound intensity is half, i.e
₂ =
₁/2
Hence,
₂/
₁ = r₁²/r₂²
1/2 = (165)²/ r₂²
r₂² = 2 × (165)²
r₂² = 2 × 27225
r₂² = 54450
r₂ = √54450
r₂ = 233.35 m
Therefore, required distance is 233.35 m
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