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Vinvika [58]
3 years ago
7

How do your skills help accomplish things for your team

Physics
1 answer:
Snowcat [4.5K]3 years ago
4 0
1. Invest in getting to know them more:if you have more rapport with your people by knowing who they are, what their passions are outside of work, and what drives them, they'll be more likely to open up.
2.Tell them their career success matters to you:if you really want them to have happy, fulfilling careers, you need to embrace that they won't work for you forever. your reward for this is that they'll work harder and love working with you or for you while they do. let them now you have that belief.
3.Share your goals first:if you trust them by sharing your goals, they are more likely to share their goals. this is it. good luck and i did my best to help you. 
4.
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W=225 J<br> P=25 W<br> t=?<br> what's T
Mama L [17]

Explanation:

p=w/t

t=w/p

t=225/25=9seconds

5 0
2 years ago
A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.Wh
alekssr [168]

(a) 392 N/m

Hook's law states that:

F=k\Delta x (1)

where

F is the force exerted on the spring

k is the spring constant

\Delta x is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N

- The stretching of the spring is

\Delta x=15 cm-10 cm=5 cm=0.05 m

Solving eq.(1) for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N

And so, the stretch of the spring is

\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm

And since the initial lenght of the spring is

x_0 = 10 cm

The final length will be

x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm

8 0
3 years ago
Read 2 more answers
Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the
Tom [10]
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
8 0
3 years ago
your friend rides her bicycle across town at a constant speed. Describe how you could determine her speed
Alchen [17]
You measure the total distance the bike travels, and the total time it takes to travel that distance. You then divide the distance by the time
6 0
3 years ago
If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step
azamat

Answer:

Explanation:

v_f^2 = v_i^2-2a(x_f-x_i)

Subtract both sides by v_i^2:

- v_i^2+v_f^2 = -2a(x_f-x_i)

Divide both sides by -2*a:

\frac{v_i^2 - v_f^2}{2a} =x_f-x_i

Add both sides by x_i:

x_i+\frac{v_i^2 - v_f^2}{2a} =x_f

Subtract both sides by \frac{v_i^2 - v_f^2}{2a}:

x_i=x_f-\frac{v_i^2 - v_f^2}{2a}

8 0
3 years ago
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