Answer:
interstellar gas clouds may collapse to from a star if they [ecounter a shock wave.]
Potential energy is the energy by virtue of object's height & kinetic energy by virtue of it's motion!
Hope this helps!
Answer:
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
39929.4542466 m
Explanation:
Total mass of the asteroids
![m_a20000\times 10^{17}=2\times 10^{21}\ kg](https://tex.z-dn.net/?f=m_a20000%5Ctimes%2010%5E%7B17%7D%3D2%5Ctimes%2010%5E%7B21%7D%5C%20kg)
= Mass of Earth = ![5.972\times 10^{24}\ kg](https://tex.z-dn.net/?f=5.972%5Ctimes%2010%5E%7B24%7D%5C%20kg)
The ratio is
![\dfrac{m_a}{m_e}=\dfrac{2\times 10^{21}}{5.972\times 10^{24}}\\\Rightarrow \dfrac{m_a}{m_e}=0.000334896182184](https://tex.z-dn.net/?f=%5Cdfrac%7Bm_a%7D%7Bm_e%7D%3D%5Cdfrac%7B2%5Ctimes%2010%5E%7B21%7D%7D%7B5.972%5Ctimes%2010%5E%7B24%7D%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bm_a%7D%7Bm_e%7D%3D0.000334896182184)
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
Volume is given by
![V=\dfrac{m}{\rho}\\\Rightarrow \dfrac{4\pi}{3\times 8} d^3=\dfrac{m}{\rho}\\\Rightarrow d^3=\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{10^{17}}{3000})^{\dfrac{1}{3}}\\\Rightarrow d=39929.4542466\ m](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7Bm%7D%7B%5Crho%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B4%5Cpi%7D%7B3%5Ctimes%208%7D%20d%5E3%3D%5Cdfrac%7Bm%7D%7B%5Crho%7D%5C%5C%5CRightarrow%20d%5E3%3D%5Cdfrac%7B3%5Ctimes%208%7D%7B4%5Cpi%7D%5Cdfrac%7Bm%7D%7B%5Crho%7D%5C%5C%5CRightarrow%20d%3D%28%5Cdfrac%7B3%5Ctimes%208%7D%7B4%5Cpi%7D%5Cdfrac%7Bm%7D%7B%5Crho%7D%29%5E%7B%5Cdfrac%7B1%7D%7B3%7D%7D%5C%5C%5CRightarrow%20d%3D%28%5Cdfrac%7B3%5Ctimes%208%7D%7B4%5Cpi%7D%5Cdfrac%7B10%5E%7B17%7D%7D%7B3000%7D%29%5E%7B%5Cdfrac%7B1%7D%7B3%7D%7D%5C%5C%5CRightarrow%20d%3D39929.4542466%5C%20m)
The diameter is 39929.4542466 m
Answer:
\frac{R}{^{\sqrt{2}}}
Explanation:
q1 = q , q2 = q
m1 = M, m2 = 2M
Potential difference is V
Let v1 be the speed of first particle and v2 be the speed of second particle.
Energy due to potential difference gives the kinetic energy to the particle.
1/2 m x v^2 = e V
v^2 = 2 e V / m = 2e V / m ... (1)
![v}=\sqrt{\frac{2eV}{m}}](https://tex.z-dn.net/?f=v%7D%3D%5Csqrt%7B%5Cfrac%7B2eV%7D%7Bm%7D%7D)
Now radius is given by
r = m v / B q
by eqution (1)
For first particle
.... (2)
For second particle
![r_{2}=\frac{\sqrt{4eMV}}{Bq}](https://tex.z-dn.net/?f=r_%7B2%7D%3D%5Cfrac%7B%5Csqrt%7B4eMV%7D%7D%7BBq%7D)
.... (3)
Divide equation (2) by equation (3), we get
![r_{1}=\frac{R}{^{\sqrt{2}}}](https://tex.z-dn.net/?f=r_%7B1%7D%3D%5Cfrac%7BR%7D%7B%5E%7B%5Csqrt%7B2%7D%7D%7D)
So
r1 / r2 =