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ale4655 [162]
3 years ago
9

A mixture of helium, argon, and xenon gases are present in a container. What is the partial pressure of helium if the total pres

sure is 49.2 kPa and the partial pressure of Ar is 15.6 kPa and 21,4 kPa for Xe?
Chemistry
2 answers:
LiRa [457]3 years ago
8 0

Answer:

P_{He} = 12.2\,kPa

Explanation:

Let assume that each gas behaves ideally, the total pressure is the sum of the pressures of each gas. Therefore:

P_{total} = P_{He} + P_{Ar} + P_{Xe}

P_{He} = P_{total} - P_{Ar} - P_{Xe}

P_{He} = 49.2\,kPa - 15.6\,kPa - 21.4\,kPa

P_{He} = 12.2\,kPa

alexandr402 [8]3 years ago
3 0

Answer:

Partial pressure of He is 12.2 KPa

Explanation:

According to Dalton law of partial pressure, the net pressure of a gaseous mixture is always equal to the sum of the partial pressures of individual gases.

Now we are given that total pressure is 49.2 KPa

Partial pressure of Ar is 15.6

Partial pressue of Xe is 21.4

Partial Pressure of He?

Using dalton's law;

49.2 = 15.6 + 21.4 + Pp of He

Partial pressure of He is 12.2 KPa

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  The arrangement of valence electrons in metals can be best described by the

A sea of electrons.

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Answer:Frequency (hz) is some sort of vibration occurs during a particular period of time as either in a sound waves or in an electromagnetic field. Given below an online frequency of light with wavelength calculator to convert from wavelength to hz. Wavelength (λ) is the distance between two waves of energy traveling from one point to another point.

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Explain why elements in the same group of the periodic table have similar chemical properties
jolli1 [7]

Answer:

                      Elements in same group have same chemical properties due to same number of valence electrons in valence shell.

Explanation:

                   Chemical properties are those properties which results in transforming the starting material to a entirely new substance with different chemical and physical properties. This transformation takes place after a chemical reaction. Hence, the chemical reactivity of some atoms is greater than the others and vice versa.

                    In periodic table it is found that the elements in the same group have almost same chemical behaviour. For example, elements of group 8 (or 18) are almost non reactive, while that of group 1 and group 7 are found very reactive and show same chemical behaviour like group 1 elements forms +1 ion while group 7 elements form -1 ions as the group 1 metals have single valence shell electron which upon losing allow the atom to attain stability and the halogen having 7 electrons in valence shell upon accepting one electron allow them to attain a octet of stability respectively.

8 0
3 years ago
011 1.0 points What energy change is associated with the reaction to obtain one mole of H2 from one wang (ew22622) – 19D Thermod
vlada-n [284]

Answer:

<em>249 kJ</em>

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>

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I hope it helps!

4 0
3 years ago
What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin
Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = \frac{1}{22.4}\times 116=5.18mol of butane

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = \frac{8}{2}\times 5.18=20.72mol of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

  • <u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = \frac{10}{2}\times 5.18=25.9mol of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0
3 years ago
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