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3 years ago

7

A dog buries a bone −1 5/6 inches into the dirt. The dog buries another bone −1 3/4 inches into the dirt. Which bone is buried d

eeper?

1 answer:

Luden [163]3 years ago

3 0

I did this test to it’s 1 5/6

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Starting time 2:15 am elapsed time 45 minutes

AveGali [126]

One hour = 60 minutes
60-15=45 so I would just add your 45 minutes to your 2:15
2:15+:45= 3:00

so your answer will be 3:00 :)

4 0

3 years ago

Dose anyone know how to do this

Neko [114]

The first one is < the second one is < and the last one is =

5 0

4 years ago

Read 2 more answers

Is 52+(-2.5) negative.

Alex777 [14]

Answer:

No, it is positive.

Step-by-step explanation:

3 0

3 years ago

What is 5(4x+12)+3x+2

yulyashka [42]

Answer:

23 x + 62

Step-by-step explanation:

Simplify the following:

5 (4 x + 12) + 3 x + 2

5 (4 x + 12) = 20 x + 60:

20 x + 60 + 3 x + 2

Grouping like terms, 60 + 20 x + 3 x + 2 = (20 x + 3 x) + (60 + 2):

(20 x + 3 x) + (60 + 2)

20 x + 3 x = 23 x:

23 x + (60 + 2)

60 + 2 = 62:

Answer: 23 x + 62

5 0

3 years ago

PLEASE HELP ASAP!!! URGENT

neonofarm [45]

Answer:

1) $\frac{\sin x}{1-\cos x} = \csc x + \cot x$

2) $\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}$

3) $\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}$

4) $\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}$

5) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}$

6) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}$

7) $\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}$

Step-by-step explanation:

Now we proceed to show all steps needed to demonstrate the trigonometric identity:

1) $\frac{\sin x}{1-\cos x} = \csc x + \cot x$ Given.

2) $\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}$ Identities for cosecant and cotangent functions.

3) $\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}$ $\frac{a}{b}+\frac{c}{b} = \frac{a+c}{b}$

4) $\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}$ Existence of additive inverse/Modulative property.

5) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}$ Fundamental trigonometric identity.

6) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}$ Factorization.

7) $\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}$ Existence of additive inverse/Modulative property/Result.

5 0

3 years ago