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Yuri [45]
3 years ago
6

How do you justify 10 (y+5) = 10

Mathematics
2 answers:
zaharov [31]3 years ago
7 0
I don't really know what you mean when you say "justify".

That's an equation in 'y'.  There's only one number that
'y' can be if the equation is a true statement.

The number is  -4 .  It's called the "solution" of the equation.
Alexeev081 [22]3 years ago
3 0
Want a word problem for it
if u do it's 10of y plus 5 is 10
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He fourth-grade students at Curtis Estabrook make up 0.3 of all students​ at the school. What fraction is equivalent to 0.3? ​
BartSMP [9]

Answer:

3/10

Step-by-step explanation:

fouth grade students at Estrabook make up 0.3 percents of the students at school

The fraction is therefore equivalent to

= 3/10

4 0
2 years ago
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8 0
3 years ago
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Sakura speaks 150 words per minute on average in Hungarian, and 190 words per minute on average in Polish. She once gave cooking
marusya05 [52]

Answer:3 minute

Step-by-step explanation:

Sakura speaks hungarian =150 words per minute

Sakura speaks polish =190 words per minute

and it is given she speaks 270 more words in polish than in hungarian

She speaks for a total of 5 minutes

let she speaks hungarian for t mins

therefore 150\times t+270=190\left ( 5-t\right )

t=2 mins

therefore sakura speaks hungarian for 2 mins and polish for 3 mins

6 0
3 years ago
how will I put this in an equation a giraffe is 4 tines as tall as a gorilla the gorilla is 6 feet tall
Mumz [18]

Answer:

WHY IS IT SO TALL

Step-by-step explanation:

WHY WHY WHY

7 0
2 years ago
Find the exact value of each trigonometric function for the given angle θ.
Kay [80]

Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

8 0
2 years ago
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