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ololo11 [35]
3 years ago
10

Which relation is a function? A. (2,4) (2,-7) (2,11) (2,-15)

Mathematics
1 answer:
RSB [31]3 years ago
5 0
The answer would be D
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Can someone help me ?
Leni [432]

Answer:

d

Step-by-step explanation:

if she connects it to any other point angle would be more the 30 degree

6 0
3 years ago
Read 2 more answers
Please help !! <33
KonstantinChe [14]

Answer:

23

Step-by-step explanation:

8 0
3 years ago
18.79+2.11+(-1.92)+17.28
stellarik [79]

Answer:

36.26

Step-by-step explanation:

Hope this helps. Plz give brainliest.

7 0
3 years ago
Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.
Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = n^{3}+2n+3n^{2}

for n=1

P(n)  = 1^{3}+2(1)+3(1)^{2} = 6

It is divisible by 2 and 3

Now, for n=k, n > 0

P(k) = k^{3}+2k+3k^{2}

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = (k+1)^{3}+2(k+1)+3(k+1)^{2}

P(k+1) = k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3

P(k+1) = P(k)+3(k^{2}+3k+2)

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = n^{3}+2n+3n^{2} is divisible by 2 and 3 for all positive integer n.

3 0
3 years ago
Subtract 5a-6b+7c from 13a-4b+8c
schepotkina [342]

Answer:

im not sure but i think the anwser is its self dont take my anwser its garbadge

Step-by-step explanation:

8 0
3 years ago
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